Simplify into a single phasor 1. v = j * omega * R / 1 +...
Simplify into a single phasor
1. v = j * omega * R / 1 + j *omega * L (where R, L, and omega are constants)
2. v = (1 - j * omega^2 * RL) / (R + omega * L * C / j)^2
doing either one would help greatly
Homework Answers
Problem number 7 Simplify the following complex expressions into a single Phasor (ie, a single complex...
Problem number 7
Simplify the following complex expressions into a single Phasor (ie, a single complex number in polar notation in the form V = Ves iT Her Tz joan 1+ where R. Landare constants) Vio where and care constants) _ 1+ V2 je 1 preview Die 9 Th w
Given for a series LRC circuit that I=V/Z and that Z=[R2+(omega L-1/(omega C))2]1/2 explain the interesting...
Given for a series LRC circuit that I=V/Z and that Z=[R2+(omega L-1/(omega C))2]1/2 explain the interesting result about the current and power to R. These result from special values of R, L, and C
.Single-Frequency Analysis VR 1 + 0000 The circuit has L 100 mH, R 1 kn, C...
.Single-Frequency Analysis VR 1 + 0000 The circuit has L 100 mH, R 1 kn, C 0.05 F, and the sinusoidal source is described by: L vg V. 10 cos(27nft+ 90°) V where f 3 kHz In this step for single-frequency analysis, find the magnitudes and phases of V VR, Vc, and the current in the series circuit by L performing an analytical solution using phasor analysis. Then, you are to use PSpice to find these same magnitudes and phases...
2. complex numbers a voltage v(t) is given: v(t)=v1(t)+v2(t)=1 V sin( omega t -45) – 2...
2. complex numbers a voltage v(t) is given: v(t)=v1(t)+v2(t)=1 V sin( omega t -45) – 2 V cos(omega t-60) a)convert the voltages to phasors and sketch a phasor diagram of V1,V2 and V b)reduce the expression of v(t) to the form v(t)=Vm cos(omega*t + fi(its angle)) do u see normaly 3 exercise _? Problem 4. laplace transform of discontinuous function for the function illustrated a) sketch f'(t) b)find la place transform of f'(t)
PROBLEM 2 1. The Lagrangian L for a single particle in a potential V(2) in one...
PROBLEM 2
1. The Lagrangian L for a single particle in a potential V(2) in one dimension is [(4,) = 5 mi? – V(x) Find the Hamiltonian H defined H2,p) = max{sip - L(r,.ic)} How does this compare to the total energy? 2. Repeat the previous problem for a single particle in a potential V (2, y, z) in three dimensions by doing a Legendre transform of the i, followed by one for y, and lastly one for 2.
4. Fig. 2 below shows a series R-L circuit: VA Fig. 1 (a) Suppose the phasor...
4. Fig. 2 below shows a series R-L circuit: VA Fig. 1 (a) Suppose the phasor Kas -12020-v at f= 60 Hz. A = 100 Ω, and L= 0.5 H. Find in the following order: (b) Now, write the expressions for current resistor voltage Kalf), and inductor voltage ws in the form (V or Alsiniot) where the represent voltage, current, or angle in degrees. Remember to multiply ms magnitudes by 1.414 to obtain peak values.
Q2) A single phase half-wave uncontrolled rectifier with RL load is shown below With R-1000 L 01H w-377rad/s and V 1...
Q2) A single phase half-wave uncontrolled rectifier with RL load is shown below With R-1000 L 01H w-377rad/s and V 100V, Determine a) An expression for the load current i(t). b) The value of the current at t 16 ms c) The average load current (10 marks) 7 RV そ0 -121 34.7 Vsinfwr) + VE 0.360
Q2) A single phase half-wave uncontrolled rectifier with RL load is shown below With R-1000 L 01H w-377rad/s and V 100V, Determine a) An...
[5.0 Marks] Simplify the block-diagram shown in Figure 1 and reduce it to a single simplified...
[5.0 Marks] Simplify the block-diagram shown in Figure 1 and reduce it to a single simplified transfer function TF(s) = C(s)/R(s) using only the simplification 'rules discussed in the lectures. Show the simplified answer in steps. In addition, the correct final transfer function answer is required that includes two polynomials: one at the numerator and one at the denominator. s + 5 R(s) - C(s) L. s + 3 S 6 s + 2 s +1. Figure 1
a. With a battery emf of 17.2 V in the RL circuit (R=0.410 2 and L=...
a. With a battery emf of 17.2 V in the RL circuit (R=0.410 2 and L= 86.0 mH), what is the self-induced emf when the switch has just been closed on a? Submit Answer Tries 0/10 What is the self-induced emf after two L/R time constants have passed? Submit Answer Tries 0/10 In units of the time constant, after how much time will the self-induced emf be just one-half of the battery emf? Submit Answer Tries 0/10
#4: Complete the following: a) Convert to phasor form: A = 10 cos (s. 10 +...
#4: Complete the following: a) Convert to phasor form: A = 10 cos (s. 10 + /4) b) Convert to phasor form: B(1,1) = 32 sin (8710'+2.r --30°) ay c) Convert the phasor A. = 35337/4 to the exact time domain form A () = A, sin (wt + o), with w = 2 10% rad/sec. Since it is not defined, you must use the baseline assumption, A, = Re 4 d) Convert from phasor to a single cosine or...
Problem number 7
Simplify the following complex expressions into a single Phasor (ie, a single complex number in polar notation in the form V = Ves iT Her Tz joan 1+ where R. Landare constants) Vio where and care constants) _ 1+ V2 je 1 preview Die 9 Th w
.Single-Frequency Analysis VR 1 + 0000 The circuit has L 100 mH, R 1 kn, C 0.05 F, and the sinusoidal source is described by: L vg V. 10 cos(27nft+ 90°) V where f 3 kHz In this step for single-frequency analysis, find the magnitudes and phases of V VR, Vc, and the current in the series circuit by L performing an analytical solution using phasor analysis. Then, you are to use PSpice to find these same magnitudes and phases...
PROBLEM 2
1. The Lagrangian L for a single particle in a potential V(2) in one dimension is [(4,) = 5 mi? – V(x) Find the Hamiltonian H defined H2,p) = max{sip - L(r,.ic)} How does this compare to the total energy? 2. Repeat the previous problem for a single particle in a potential V (2, y, z) in three dimensions by doing a Legendre transform of the i, followed by one for y, and lastly one for 2.
4. Fig. 2 below shows a series R-L circuit: VA Fig. 1 (a) Suppose the phasor Kas -12020-v at f= 60 Hz. A = 100 Ω, and L= 0.5 H. Find in the following order: (b) Now, write the expressions for current resistor voltage Kalf), and inductor voltage ws in the form (V or Alsiniot) where the represent voltage, current, or angle in degrees. Remember to multiply ms magnitudes by 1.414 to obtain peak values.
Q2) A single phase half-wave uncontrolled rectifier with RL load is shown below With R-1000 L 01H w-377rad/s and V 100V, Determine a) An expression for the load current i(t). b) The value of the current at t 16 ms c) The average load current (10 marks) 7 RV そ0 -121 34.7 Vsinfwr) + VE 0.360
Q2) A single phase half-wave uncontrolled rectifier with RL load is shown below With R-1000 L 01H w-377rad/s and V 100V, Determine a) An...
[5.0 Marks] Simplify the block-diagram shown in Figure 1 and reduce it to a single simplified transfer function TF(s) = C(s)/R(s) using only the simplification 'rules discussed in the lectures. Show the simplified answer in steps. In addition, the correct final transfer function answer is required that includes two polynomials: one at the numerator and one at the denominator. s + 5 R(s) - C(s) L. s + 3 S 6 s + 2 s +1. Figure 1
a. With a battery emf of 17.2 V in the RL circuit (R=0.410 2 and L= 86.0 mH), what is the self-induced emf when the switch has just been closed on a? Submit Answer Tries 0/10 What is the self-induced emf after two L/R time constants have passed? Submit Answer Tries 0/10 In units of the time constant, after how much time will the self-induced emf be just one-half of the battery emf? Submit Answer Tries 0/10
#4: Complete the following: a) Convert to phasor form: A = 10 cos (s. 10 + /4) b) Convert to phasor form: B(1,1) = 32 sin (8710'+2.r --30°) ay c) Convert the phasor A. = 35337/4 to the exact time domain form A () = A, sin (wt + o), with w = 2 10% rad/sec. Since it is not defined, you must use the baseline assumption, A, = Re 4 d) Convert from phasor to a single cosine or...
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