A random sample of 11 employees produced the following data, where x is the consecutive hours worked, and y is current employee satisfaction (out of a maximum of 100 points). The data are presented below in the table of values.
x | y |
---|---|
4 | 86 |
5 | 76 |
7 | 92 |
8 | 71 |
10 | 63 |
11 | 70 |
12 | 58 |
14 | 57 |
16 | 49 |
18 | 45 |
19 | 46 |
What is the equation of the regression line?
ˆ=−3.864x+97.1
yˆ=−3.864x+87.3
yˆ=−2.864x+97.1
yˆ=−1.864x+87.3
X | Y | XY | X^2 | Y^2 |
4 | 86 | 344 | 16 | 7396 |
5 | 76 | 380 | 25 | 5776 |
7 | 92 | 644 | 49 | 8464 |
8 | 71 | 568 | 64 | 5041 |
10 | 63 | 630 | 100 | 3969 |
11 | 70 | 770 | 121 | 4900 |
12 | 58 | 696 | 144 | 3364 |
14 | 57 | 798 | 196 | 3249 |
16 | 49 | 784 | 256 | 2401 |
18 | 45 | 810 | 324 | 2025 |
19 | 46 | 874 | 361 | 2116 |
From the above table and formula we get the value are as:
n | 11 |
sum(XY) | 7298.00 |
sum(X) | 124.00 |
sum(Y) | 713.00 |
sum(X^2) | 1656.00 |
sum(Y^2) | 48701.00 |
b | -2.864 |
a | 97.1 |
ycap = a +bx
Ycap = 97.1 - 2.864x
yˆ=−2.864x+97.1
A random sample of 11 employees produced the following data, where x is the consecutive hours...
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RANGES
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RELATIVE FREQUENCY
CUMULATIVE REL. FREQ.
1 - 10
11 - 20
21 - 30
31 - 40
41 - 50
51 - 60
61 - 70
71 - 80
81 - 90
91 - 100
'= 100 DATA
VALUES??
SO, WHAT DOES A FREQUENCY TABLE TELL US?
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