Question

Trace the flow of execution and give the output of the following code: int x=23; try...

Trace the flow of execution and give the output of the following code:

int x=23;

try {

x=x+1;
  throw new NumberFormatException();

}

catch (Exception e) {

x=x+2;

}

finally {

x=x+3;

}

System.out.println(x);

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Answer #1

int x=23;

try {

x=x+1;
throw new NumberFormatException();

}

catch (Exception e) {

x=x+2;

}

finally {

x=x+3;

}

System.out.println(x);

the output will be 29 as we initialized x with 23
then we entered try block where x=x+1 is executed
after this x=24
numberformatexception is thrown
which is caught by the catch block where
x=x+2 is executed
after this x=26
finally block is always executed so we enter finally block
where x=x+3 is executed
after this x=29
then we print the value of x which is 29
so the output of this whole program will be 29

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