Question

A bank claims that the mean waiting time in line is less than 4.1 minutes. A random sample of 60 customers has a mean of 4 minutes. Assuming a population standard deviation of 0.6 minute, test the bank's claim with an ? = 0.05 level of confidence. ?0 = ___________________________________ ?? = ___________________________________ Test Statistic = __________________________ Alpha level of significance= __________________ Classical Critical Value = ____________________ P-value = _______________________________ ________Conclusion: A) reject ?0 B) fail to reject ?0 ________Interpretation: A) There is sufficient evidence to support the claim. B) There is insufficient evidence to support the claim.

Answer 1

Solution :

This is the left tailed test .

The null and alternative hypothesis is ,

H₀ :   = 4.1

H_a : < 4.1

Test statistic = z

= ( - ) / / n

= (4 - 4.1) / 0.6 / 60

= -1.29

level of significance = = 0.05

P(z < -1.29) = 0.0985

P-value = 0.0985

P-value >

Fail to reject the null hypothesis .

B) There is insufficient evidence to support the claim.