Consider the following decay: 23191 Pa → 22789 Ac + α. 23191 Pa has a mass of 231.035884 u, 22789 Ac has a mass of 227.0277521 u, and α has a mass of 4.002603 u.
Determine the disintegration energy (Q-value) in MeV.
Q =
Determine the KE of the daughter in MeV.
KED =
Determine the KE of the α particle in MeV & as a factor of Q.
KEα =
KEα = Q×
Determine the speed of the α particle in terms of c. For an α particle, Eo = 3.727 GeV/c2.
valpha = x c
Consider the following decay: 23191 Pa → 22789 Ac + α. 23191 Pa has a mass of...
Consider the following decay: 236 Np 232 Pa + a. 236 Np has a mass of 236.04657 u, 232 Pa has a mass of 232.038592 u, and a has a mass of 4.002603 u. Determine the disintegration energy (Q-value) in Mev. Determine the KE of the daughter in Mev. KED = Determine the KE of the a particle in MeV & as a factor of Q. KE. = KE, = 0x Determine the speed of the a particle in terms...
Suppose some nucleus undergoes decay, releasing 5.4 MeV of energy. If the daughter product of this reaction is 93X237 (atomic mass = 237.04816) , it will recoil away as the particle leaves. Determine (a) the energy of the daughter product and (b) the energy of the particle (atomic mass = 4.002603 u). Assume that the energy of each particle is kinetic energy, and ignore any other small amounts of energy that might be carried away by other emissions. In addition,...
86X212 (atomic mass = 211.99068 u) undergoes decay. Assuming all the released energy is in the form of kinetic energy of the particle (atomic mass = 4.002603 u) and ignoring the recoil of the daughter nucleus (84X1208 atomic mass = 207.98123 u), find the speed of the particle. Ignore relativistic effects. Number Units
Calculate the energy (in MeV) released when ? decay converts uranium 232U (atomic mass = 232.037146 u) into thorium 228Th (atomic mass = 228.028731 u). The atomic mass of an ? particle is 4.002603 u.
(a) Write the decay equation for the a decay of 228 *Th. (Enter your answer in the form ^x.) chemPad Help x. Greek (b) What energy (in MeV) is released in this decay? The mass of the daughter nuclide is 224.00679 u. (Assume 1 u = 931.5 MeV/c2. Give your answer to at least 2 decimal places.) MeV (c) Assuming the residual nucleus is formed in its ground state, how much energy (in MeV) goes to the a particle? (Give...
(a)Calculate the energy (in MeV) released in the α decay of 236U. (Assume 1 u = 931.5 MeV/c2.) (b)What fraction of the mass of a single 236U is destroyed in the decay? The mass of 232Th is 232.038054 u.
Calculate the energy (in MeV) released when a decay converts uranium 232u (atomic mass = 232.037146 u) into thorium 228Th (atomic mass = 228.028731 u). The atomic mass of an a particle is 4.002603 u. 9.65MeV Submit Answer Incorrect. Tries 4/10 Previous Tries
3) The disintegration energy Q during a decay must be sharred by the alpha particle and the daughter nucleus in order to conserve both energy and momentum in the decay process. (a) Show that Q and Ka, the kinetic energy of the alpha particle, are related by the expression Q=K,(1+ where My is the mass of the daughter nucleus. (8 pts) (b) Use the result of (a) to find the energy of the alpha particle emitted in the decay of...
A polonium isotope with an atomic mass of 218.008973 u undergoes alpha decay, resulting in a daughter isotope with an atomic mass of 213.999805 u. lgnoring any recoil of the daughter, find the kinetic energy of the emitted alpha particle in megaelectronvolts (MeV) Number MeV
AU-238 atom undergoes alpha decay. The daughter atom then undergoes beta minus decay into a second daughter atom. What is the second daughter atom? 0 U-235 Th-238 Th-234 O Pa-234 O Rn-222 Question 20 AU-238 atom (uranium-238) has a nucleus with 92 protons and an atomic mass of 238.0507882 u. What is the nuclear binding energy per nucleon in this atom? O 1.93 MeV 0 7.57 MeV O 12.3 MeV O 19.6 MeV O 1802 MeV