How do you know when the object distance should be negative in a two lens problem?...
How do you know when the object distance should be negative in a two lens problem? Say for instance an object is 30 cm to the left of a diverging lens. Is object distance positive or negative? Is this the same for a converging lens?
Homework Answers
If the object/ image is left side of any kind of lens, the sign convention is taken as negative and vice versa. Therefore distance of object should be taken as negative whether lens is converging/ diverging.
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How do you know when the object distance should be negative in a
two lens problem?...
When an object is placed at the proper distance to the left of a converging lens,...
When an object is placed at the proper distance to the left of a converging lens, the image is focused on a screen 30.0 cm to the right of the lens. A diverging lens with focal length f= -24 cm is now placed 15.0 cm to the right of the converging lens. a) How much do you need to move the screen farther to obtain a sharp image? Indicate if the screen should be moved to the right or to...
An object is a distance 16.9cm to the left of a converging lens ("Lens 1") with...
An object is a distance 16.9cm to the left of a converging lens ("Lens 1") with a focal length of 20cm. Lens 1 is itself a distance 30cm to the left of a second converging lens ("Lens 2") with a focal length 20cm. The object is along the optical axis of the two-lens system. What is the magnification of the image due to Lens 1? If the image is inverted your answer should be negative, and if it is upright...
An object is placed 50.0cm in front of a lens. The image forms on the same...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real
An object is placed 50.0cm in front of a lens. The image forms on the same...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O upright, converging, positive, virtual O inverted, converging, positive, real inverted, diverging, negative, real O upright, converging, negative, virtual O inverted, diverging, positive, real O inverted, converging, positive, virtual O upright, converging, positive, real O...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
Two lenses are placed a distance of 20.0 cm apart. The leftmost lens is a converging...
Two lenses are placed a distance of 20.0 cm apart. The leftmost lens is a converging lens with a focal length of 10.0 cm while the seconds lens is a diverging lends with a focal length of 13.0. If an object is placed 4.0 cm to the left of the converging lens, determine the magnification of the two lenses combined.
A converging lens is placed at x = 0, a distance d = 11.5 cm to...
A converging lens is placed at x = 0, a distance d = 11.5 cm to the left of a diverging lens as in the figure below (where F and Flocate the focal points for the converging and the diverging lens, respectively). An object is located at x = -1.60 cm to the left of the converging lens and the focal lengths of the converging and diverging lenses are 4.50 cm and -8.10 cm, respectively, HINT FO to ro (a)...
An object is placed to the right of a converging lens and an image is formed...
An object is placed to the right of a converging lens and an image is formed to the left of the lens. lens object image 1) Following the standard sign convention for the lens equation 5 + 5 = }, the image distance is: positive negative Submit 2) The image is: real virtual Submit 3) For this lens, the sign of the focal length is: positive negative Submit Help 4) An object is placed to the left of a converging...
Two systems are formed from a converging lens and a diverging lens, as shown in parts...
Two systems are formed from a converging lens and a diverging
lens, as shown in parts a and b of the drawing. (The point labeled
"Fconverging" is the focal point of the converging lens.) An object
is placed inside the focal point of lens 1 at a distance of 6.4 cm
to the left of lens 1. The focal lengths of the converging and
diverging lenses are 15.0 and -20.0 cm respectively. The distance
between the lenses is 50.0 cm....
help me Question 3) An object with height 1.sotem) (the thick arrow in de converging converging lens. There is a distance from each lens to its own focal point is 15.olem diagram) is 33.0fem] t...
help me
Question 3) An object with height 1.sotem) (the thick arrow in de converging converging lens. There is a distance from each lens to its own focal point is 15.olem diagram) is 33.0fem] to the left of a diverging lens that is 50.0[cm] to the right of the converging lens. The neha he scale is different in the vertical and horizontal directions (Be careful about sign conventions) DivergiNg Lens Converging Lens Object 1.50 cm 15.0 cm-15.0cm 15.0cm -5.0cm 33.3...
When an object is placed at the proper distance to the left of a converging lens, the image is focused on a screen 30.0 cm to the right of the lens. A diverging lens with focal length f= -24 cm is now placed 15.0 cm to the right of the converging lens. a) How much do you need to move the screen farther to obtain a sharp image? Indicate if the screen should be moved to the right or to...
An object is a distance 16.9cm to the left of a converging lens ("Lens 1") with a focal length of 20cm. Lens 1 is itself a distance 30cm to the left of a second converging lens ("Lens 2") with a focal length 20cm. The object is along the optical axis of the two-lens system. What is the magnification of the image due to Lens 1? If the image is inverted your answer should be negative, and if it is upright...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O upright, converging, positive, virtual O inverted, converging, positive, real inverted, diverging, negative, real O upright, converging, negative, virtual O inverted, diverging, positive, real O inverted, converging, positive, virtual O upright, converging, positive, real O...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
A converging lens is placed at x = 0, a distance d = 11.5 cm to the left of a diverging lens as in the figure below (where F and Flocate the focal points for the converging and the diverging lens, respectively). An object is located at x = -1.60 cm to the left of the converging lens and the focal lengths of the converging and diverging lenses are 4.50 cm and -8.10 cm, respectively, HINT FO to ro (a)...
An object is placed to the right of a converging lens and an image is formed to the left of the lens. lens object image 1) Following the standard sign convention for the lens equation 5 + 5 = }, the image distance is: positive negative Submit 2) The image is: real virtual Submit 3) For this lens, the sign of the focal length is: positive negative Submit Help 4) An object is placed to the left of a converging...
Two systems are formed from a converging lens and a diverging
lens, as shown in parts a and b of the drawing. (The point labeled
"Fconverging" is the focal point of the converging lens.) An object
is placed inside the focal point of lens 1 at a distance of 6.4 cm
to the left of lens 1. The focal lengths of the converging and
diverging lenses are 15.0 and -20.0 cm respectively. The distance
between the lenses is 50.0 cm....
help me
Question 3) An object with height 1.sotem) (the thick arrow in de converging converging lens. There is a distance from each lens to its own focal point is 15.olem diagram) is 33.0fem] to the left of a diverging lens that is 50.0[cm] to the right of the converging lens. The neha he scale is different in the vertical and horizontal directions (Be careful about sign conventions) DivergiNg Lens Converging Lens Object 1.50 cm 15.0 cm-15.0cm 15.0cm -5.0cm 33.3...
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