Molar mass of CFCl3,
MM = 1*MM(C) + 1*MM(F) + 3*MM(Cl)
= 1*12.01 + 1*19.0 + 3*35.45
= 137.36 g/mol
mass(CFCl3)= 70 Kg
= 70000 g
use:
number of mol of CFCl3,
n = mass of CFCl3/molar mass of CFCl3
=(7*10^4 g)/(1.374*10^2 g/mol)
= 5.096*10^2 mol
This is number of moles of CFCl3
one mole of CFCl3 contains 3 mole of Cl
use:
number of moles of Cl = 3 * number of moles of CFCl3
= 3 * 5.096*10^2
= 1.529*10^3
Molar mass of Cl = 35.45 g/mol
use:
mass of Cl,
m = number of mol * molar mass
= 1.529*10^3 mol * 35.45 g/mol
= 5.42*10^4 g
= 54.2 Kg
Answer: 54.2 Kg
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can you show all the steps
can
you calculate mole of water ,mass of chlorine in sample, moles of
chlorine, mole ration ,chlorine : copper in sample , formaula of
degydrated sample and formula of hudrated sample using the data
from page 1
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