question 1) if 520.0 J are added to 150g of water at 30C, what will be...
question 1) if 520.0 J are added to 150g of water at 30C, what will be the final temperature of water?
question 2) if 520.0 J are removed to 150g of water at
30C, what will be the final temperature of water?
...
I tried doing question 1 but I didnt understand how come the answer
of the change of temperature of 0.8280 was changed to 8.3 C and
then added with 30.0 to get the answer final temperature of 38.3 C.
why was the decimal place move to 8.3 in change in temperature.
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question 1) if 520.0 J are added to 150g
of water at 30C, what will be...
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1. A volume of water was heated to 83.90 °C and immediately added to 48.11 mL of water at 23.98 °C contained within a coffee cup calorimeter. The final temperature of the mixture was 40.86 °C. The final volume of water inside the calorimeter was 90.45 mL. Assuming that them heat capacity of the solution is 4.18 J/g/°C, calculate the following: a. The volume of hot water added ml b. The mass of hot water (dwater = 1.00 g/mL) c....
Procedure:
1. 10 Test tubes were labelled
(0C,0E,15C,15E,30C,30E,45C,45E,60C, and 60E.)
2. 2 mL cathecol-buffer at pH 6 was added into each test
tubes.
3. 3.5 mL of water was added into all of the C tubes
(0C,15C,30C,45C, and 60C.)
4. 3 mL of water was added into the remaining tubes.
5.The two tubes were put into an ice bath.
6. 0.5 mL of enzyme polyphenoloxidase was added into tube E when
the mixture had reached certain T (O°C)
7.The transmittance...
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DO ALL PARTS OF THE QUESTION AND USE SIGNIFICANT FIGURES!!! IF
YOU DO NOT DO THIS I WILL DOWNVOTE YOU!!!!
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i got this question wrong. the book previously said that the
units of entropy are J/(mol*K). you can get mol with the grams that
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