Initial concentrations (M) | |||
Mixture | [XY] | [X] | [Y] |
A | 0.100 | 0 | 0 |
B | 0.500 | 0.100 | 0.100 |
C | 0.200 | 0.300 | 0.300 |
PART B:
Based on a Kc value of 0.230 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively?
Express the molar concentrations numerically.
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Initial concentrations (M) Mixture [XY] [X] [Y] A 0.100 0 0 B 0.500 0.100 0.100 C...
Based Initial concentrations (M) Mixture [XY] [X] [Y] A 0.100 0 0 B 0.500 0.100 0.100 C 0.200 0.300 0.300 Part B: Based on a Kc value of 0.150 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Part C: Based on a Kc value of 0.150 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively? Please show work and make sure it's correct
Initial concentrations (M) Mixture [XY] X] [Y] A 0.10000 0.500 0.100 0.100 C 0.200 0.300 0.300 Part B Based on a K value of 0.240 and the given data table, what are the equilibrium concentrations of XY, X and Y respectively? Express the molar concentrations numerically. View Available Hint(s) ΑΣφ [XY], [X], [Y] 0.255,0.245,0.245 Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining Part C Based on a K value of 0.240 and the data table given, what are...
Based on a XY, X, and Y, respectively? Kc value of 0.250 and the given data table, what are the equilibrium concentrations of Express the molar concentrations numerically. View Available Hint(s) να ΑΣφ ? XY, X, [Y] M Based on a Kc value of 0.250 and the initial concentrations given in the table, determine in which direction the net reaction will proceed to attain equilibrium. Initial concentrations (M) XY Mixture XY 0.100 0 0 0.500 0.100 0.100 B 0.200 0.300...
Based on a Kc value of 0.140 and the initial concentrations given in the table, determine in which direction the net reaction will proceed to attain equilibrium. Initial concentrations (M) Mixture [XY] [X] [Y] A 0.100 0 0 B 0.500 0.100 0.100 C 0.200 0.300 0.300 Part A Based on a Kc value of 0.140 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Part B Based on a Kc value of 0.140...
Calculating equilibrium concentrations when the net reaction proceeds forward Consider mixture B, which will cause the net reaction to proceed forward. net → [X] + 0:00 Concentration (M) (XY) initial: 0.500 change: equilibrium: 0.500 - 2 [Y] 0.100 + 0.100 + +x 0.100+ The change in concentration, 2, is negative for the reactants because they are consumed and positive for the products because they are produced, Part B Review | Constants Periodic Tabl Based on a Kc value of 0.250...
1. Based on a Kc value of 0.150 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. 2. Based on a Kc value of 0.150 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively? Initial concentrations (M) Mixture [XY] [X] [Y] A 0.100 0 0 B 0.500 0.100 0.100 C 0.200 0.300 0.300
1. Consider mixture B, which will cause the reaction to proceed forward: Concentration (M) [XY] <---> [X] + [Y] Initial 0.5 0.1 0.1 Change - x +x + x Equilibrium 0.5 - x 0.1 + x 0.1 + x Based on a Kc value of 0.140 the given data table, what are the equilibrium concentrations of XY, X, and Y respectively? Express the molar concentrations numerically 2. Consider mixture C, which will cause the net reaction to proceed in reverse...
Based on a Kc value of 0.150 and the initial concentrations given in the table, determine in which direction the net reaction will proceed to attain equilibrium. Will Mixture A, Mixture B, and Mixture C either go: 1) forward, or 2) reverse? Initial concentrations (M) Mixture [XY] [X] [Y] A 0.100 0 0 B 0.500 0.100 0.100 C 0.200 0.300 0.300
Calculating equilibrium concentrations when the net reaction proceeds in reverse Consider mixture C, which will cause the net reaction to proceed in reverse. Concentration (M)initial:change:equilibrium:[XY]0.200+x0.200+x←net⇌[X]0.300−x0.300−x+[Y]0.300−x0.300−x The change in concentration, x, is positive for the reactants because they are produced and negative for the products because they are consumed. Part C Based on a Kc value of 0.160 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically.
Calculating equilibrium concentrations when the net reaction proceeds in reverse Consider mixture C, which will cause the net reaction to proceed in reverse. Concentration (M)initial:change:equilibrium:[XY]0.200+x0.200+x←net⇌[X]0.300−x0.300−x+[Y]0.300−x0.300−x The change in concentration, x, is positive for the reactants because they are produced and negative for the products because they are consumed. Part C Based on a Kc value of 0.170 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically.