Problem 1: A lamp which is 10.5 cm tall is 3.7 m in front of a converging lens which has a focal length of 39.5 cm. Part (a) What is the image distance (in meters) for this lamp and lens combination (include sign if negative)? If a screen is placed at the image location found in (a), what will be observed on the screen? If the screen is moved slightly farther from the lens than the distance found in (a), what will be observed on the screen?
An object 15 cm tall is placed 80 cm in front of a converging lens with a focal length of 20 cm. a. find the image location b. what is the magnifications? c. what is the height of the image?
Problem 3: An object of height 2.8 cm is placed 26 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. a) Find the location of the final image, in centimeters beyond the converging lens (such that a negative answer would indicate the final image is on the same side of the converging lens as the object). b) What...
A 4.5–cm–tall object is 28 cm in front of a converging lens with a focal length of 36 cm. Where is the image? Distance(cm)____
(4%) Problem 18: An object of height 2.9 cm is placed 29 cm in front of a diverging lens of focal length 15 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. 50% Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to...
An object 10 cm tall is placed 50 cm in front of a diverging lens with a focal length of 10 cm. a. find the image location b. what is the magnifications? c. what is the height of the image?
An object of height 3.6 cm is placed at 24 cm in front of a diverging lens of focal length, f = -18 cm. Behind the diverging lens, there is a converging lens of focal length, f = 18 cm. The distance between the lenses is 5 cm. In the next few steps, you will find the location and size of the final image. Where is the intermediate image formed by the first diverging lens? Image distance from first lens...
1. A 1.0-cm-tall object is 85cm in front of a converging lens that has a 35cm focal length. Calculate the image position and image height. 2. A 4.0-cm-tall object is 16cm in front of a diverging lens that has a -20cm focal length. Calculate the image position and image height. 3. A 4.0-cm-tall object is 14cm in front of a concave mirror that has a 25 cm focal length. Calculate the image position and image height.
An object of height 3.6 cm is placed at 24 cm in front of a diverging lens of focal length, f = -18 cm. Behind the diverging lens, there is a converging lens of focal length, f = 18 cm. The distance between the lenses is 5 cm. In the next few steps, you will find the location and size of the final image. Where is the intermediate image formed by the first diverging lens? Image distance from first lens...
A 2.0 cm tall object is placed 10.0 cm in front of converging lens of focal length 8 cm. What can you say about the image formed by the lens? de the image is real, magnified and inverted the image is virtual, diminished and inverted O the image is virtual, magnified and upright the image is real, magnified and upright the image is real, diminished and inverted
A 4.0 cm tall object is placed 12.0 cm in front of a diverging lens. When the image of the object is measured it is found to measure 1.3 cm in height. What is the focal length of the lens? Draw a ray diagram with the object, image and focal points labeled.