A 1-mL solution of 0.05 M H2SO4, is diluted to 100 mL at 25 degrees C. What is the pH of the resulting solution?
a. 1
b. 2
c. 3
d. 4
Please explain the reasoning
PH would be 3 because
concentration of H ion will be from H2SO4 only
M1V1 = M2V2
0.05(1)=M2100
M2=510(4minus)
N= 2 (510(4minus)
N=110(3minus)
pH= -logH+
pH= -log110(3minus)
pH=3
A 1-mL solution of 0.05 M H2SO4, is diluted to 100 mL at 25 degrees C....
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