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The mean amount of money spent on lunch per week for a sample of 75 students...

The mean amount of money spent on lunch per week for a sample of 75 students is $42. If the margin of error for the population mean with a 99% confidence interval is 2.10, construct a 99% confidence interval for the mean amount of money spent on lunch per week for all students.

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Answer #1

Confidence interval formula is

where , E= margin of error = 2.10

Substitute here known values

=>(39.9,44.1)

Therefore,   a 99% confidence interval for the mean amount of money spent on lunch per week for all students

is ($39.9 , $44.1)

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