Find the number of atoms in a copper rod with a length of 9.20 cm and a radius of 1.00 cm. The density of copper is 8.96 g/cm3.
Length=9.2cm
Radius=1cm
Density=8.96g/cm^3
Vol of rod=pi× radius×radius×length=3.14×1×1×9.2=28.9cm^3
Mass=density × volume=8.96 × 28.9=259g
Molar mass of copper= 63.55 g/mol
This implies 259g will have 259/63.55 mol =4 mol
We know that 1 mol = 6.022 ×10^23 atoms
Hence 4 mol= 4×6.022 × 10^23 atoms = 2.4088 × 10^24 atoms
Find the number of atoms in a copper rod with a length of 9.20 cm and...
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