The Ksp of PbSO4 is 1.3 x 10-8. What is the concentration of Pb2+ ions in...

Question

Question

The Ksp of PbSO₄ is 1.3 x 10^-8. What is the concentration of Pb²⁺ ions in a saturated solution of PbSO₄?

Answer 1

Answer #1

given Ksp = 1.3 * 10^(-8)

PbSO4~~>Pb²⁺ + SO₄^2-

Ksp = [Pb2+] [SO₄^2-]

1.3 * 10^(-8) = x. x = x^(2)

x =(1.3 * 10^(-8))^1/2

x = 1.14 * 10^(-4) M

thus concentration of Pb2+ is 1.14 *10^(-4) in saturated solution of PbSO4 which we calculated by using formula of Ksp.

Answer 2

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