(1 point) When a proton has a velocity v=(5i^+8j^)×106m/s, it experiences a force F=−1.8×10−13k^N. In a second experiment with the same B field, the particle is moving along the +zaxis, and under these new conditions it experiences a force along the +xaxis. What is the magnetic field?
(1 point) When a proton has a velocity v=(5i^+8j^)×106m/s, it experiences a force F=−1.8×10−13k^N. In a...
A proton is moving with a velocity j = (2 x 106m/s) î + 3 x 10m/sſ in a constant magnetic field B = 0.21 Î - 0.5 Th. What is the magnetic force on the proton? 6.4 x 10-13k N -6.4 x 10-13N (6.4 x 10-249 - 2.4 x 10-137N (-2.56 x 10-13R) N
A proton moves with a velocity of v-(3i-j+k) m/s in a region in which the magnetic field is B - +2j-i)T. What is the magnitude of the magnetic force this particle experiences? A proton moves with a velocity of v-(3i-j+k) m/s in a region in which the magnetic field is B - +2j-i)T. What is the magnitude of the magnetic force this particle experiences?
A proton moves with a velocity of v with arrow = (6î − 4ĵ) m/s in a region in which the magnetic field is B with arrow = (î + 2ĵ) T. What is the magnitude of the magnetic force this particle experiences?
A proton moves with a velocity of v = (59 - 5j + k) m/s in a region in which the magnetic field is B = (Î + 2) - k) T. What is the magnitude of the magnetic force this particle experiences? N
A proton moving in a uniform magnetic field with v⃗ 1=1.13×106ı^m/s experiences force F⃗ 1=1.70×10−16k^N. A second proton with v⃗ 2=2.06×106ȷ^m/s experiences F⃗ 2=−4.17×10−16k^N in the same field. What is the magnitude of B⃗ ? What is the direction of B⃗ ? Give your answer as an angle measured ccw from the +x-axis.
A proton moves with a velocity of V (ai 6j m/s in a region in which the magnetic field is B i2j - k) T. What is the magnitude of the magnetic force this particle experiences? Need Help?Read ItWatch t
A proton, traveling with a velocity of 3.1 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 6.6 × 10-14 N and direction of due south. What are the magnitude and direction of the magnetic field causing the force? If the field is up, then enter a number greater than zero. If the field is down, then enter a number less than zero. An α-particle has a charge of +2e and a mass of...
Question 14 20 pt A proton moves with a velocity of v = (2 i-5j+k)m/s in a region in which the magnetic field is B = (i+2j-2 k) T. What is the the magnitude and direction of the magnetic force this particle experiences? Upload Choose a File < Previous o e
1. A proton is a moderately strong electric field experiences an electric force of F=10-14 N. How long would it take this field to accelerate the proton from the rest (v0=0) to 80% of the speed of light (v=0.8c)? Hint: F= (Δp/t); p= mv= m0v/[(1-v2/c2)]1/2 . (Ans.: 66.9 μs).
An electron with velocity v⃗ =(3ax^+2ay^+2az^)×10^5m/s experiences zero net force at a point in the magnetic flux density B⃗ =(3ax^+7ay^+3az^)mWb/m2. Find the magnitude of the electric field E⃗ at that point. 1 point An electron with velocity U-(3a -2ay + 2a.) x 105 m/s experiences zero net force at a point in the magnetic flux density B mWb/m2. Find the magnitude of the electric field E at that point. (Заг + ra, + 36) kV/m