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Q1. How many extra electrons reside on pith balls? Know that the charge of the electron...

Q1. How many extra electrons reside on pith balls? Know that the charge of the electron is

       1.602 x 10-19 C.

Value of charge between both pith balls =6.618*10^-9

Mass per pith ball =0.05g

The angle θ between the string and the vertical line (measured by the protractor): 6°

The separation distance r between the centers of the pith balls: 8.2 cm

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Answer #1

the no of electrons are " n "

n = Q / e

= 6.618 x 10-9 / 1.602 x 10-19

n = 4.131 x 1010 electrons

the gravitational force Fg = G m m / d2

= 6.67 x 10-11 x 0.052 x 10-6 / 0.0822  

the gravitational force Fg = 2.4799 x 10-17 N

the electric force is FE = k q2 / d2

= 9 x 109 x ( 6.618 x 10-9 )2 / 0.0822

the electric force is FE = 5.862 x 10-5 N

the horizontal force is FH = m g tan6

= 0.05 x 10-3 x 9.8 x tan6

the horizontal force is FH = 5.15 x 10-5 N

the vertical force is = m g

= 0.05 x 10-3 x 9.8

the vertical force is FV = 4.9 x 10-4 N

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