A rock thrown with speed 6.00 m/s and launch angle 30.0 ∘ (above the horizontal) travels...
A rock thrown with speed 6.00 m/s and launch angle 30.0 ∘ (above the horizontal) travels a horizontal distance of d = 16.5 m before hitting the ground. From what height was the rock thrown? Use the value g = 9.800 m/s2 for the free-fall acceleration.
Find the height yi from which the rock was launched.
Homework Answers
using the equation
X = Ux*t
16.5 = 6 cos 30 *t
t = 3.17 s
Y = Uyt - 0.5gt^2
Y = 6sin 30 *3.17 - 0.5*9.8*3.17^2
Y = -39.88 m
so rounding off height is 39.88 m
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