Problem 47.- A dc motor develops 55 N-m of torque at a speed of 600 rad/s when12 volts are applied. It stalls out at this voltage with 100 N-m of torque. If the inertiaand damping of the armature are 7 kg-m^2 and 3 N-m-s/rad, respectively, find the transferfunction G(s) = θL(s)/Ea (s) of this motor, if it drives an inertia load of 105 kg-m^2 through a gear train, as shown in the Figure [Section: 2.8]
Notice that the following torque-speed curve can be drawn from the data given:
Problem 47.- A dc motor develops 55 N-m of torque at a speed of 600 rad/s...
Consider the DC motor-driven wheeled mobile robot shown in figure, in which m is the mass of the wheeled mobile robot, r is the radius of the driving wheel, and T is the torque delivered to the wheeled mobile robot by the DC motor. For simplicity, the motion is restricted to one spatial dimension. The figure also shows the simplified drive system, including the equivalent electrical circuit of the DC motor, the gears, and the driving wheel. The motor parameter...
Problem-5 (20 pts): Consider the DC servo motor shown in Figure-5. Assume that the input of the system is the applied armature voltage ea and the output is the load shaft position θ2. Assume also the following numerical values for the components: Ra-) Armature winding resistance = 0.2Ω La → Armature winding inductance = 0.1 mH Kb-) Back emf constant 0.05 Vs/rad K > Motor torque constant 0.06 Nm/A Jr Moment of inertia of the rotor of the motor =...
Draw the diagram for the unity feedback control system, that is, the electro-mechanical system with controller and feedback using general parameters. 3) 4) Calculate K and K using the Torque-Speed curve (Figure 2), and information from Table 1 the translational link. The robot has an torque motor for a joint in Flgure1 ropresents a Single Joint robot model wnh Figure 1: Singla Joint Robot Model TONm) 恭.east Figure 2: Torque-Speed Qurve J Ikgm21-Armature Inertia DArmature Damping Coefficient R, [ohm]-Armature Resistance...
01- (08 Pts) Figure below is a diagram of a DC motor connected in parallel to a current source is the torque and back-EMF constants of the motor are K. K respectively, the motor resistance is R, also modeled as connected in parallel, the motor inertia is I. (not shown), and the motor inductance is negligible. The motor load is an inertia compliance (stiffness) K and viscous friction coefficient b, and it is attached to the motor via a gear...
An armature-controlled dc motor operates at steady state, with an armature drive voltage va = 10 V. The motor runs at 600 rpm, and the armature current is found to be ia = 0.2 A. The armature resistance is Ra = 15 Ω. Determine: (a) The torque constant km of the motor (b) Electrical damping constant be (c) The efficiency under the given operating conditions, if the mechanical damping constant is bm = 8.25 × 10−5 N ⋅ m/rad/s (d)...
A motor drives a load requiring 0.006 N-m. Motor data is as follows: armature resistance, 4 ohms; applied voltage, 8 volts; torque constant (KT), 0.06 N-m/A; generating constant (KE), 0.0026 volts/rpm. Find the motor's running speed.
otor shown below is controlled by the armature voltage va and load torque ease i ngular velocity w, and ts is the back-emf generated by op a model (first order differential equation) of armature current i in terms velop a model (irst order differential equation) of motor output speed w in terms ta and w as state variables, and va and Ti as inputs, write the state equations the motor. complete the following of motor output speed w and input...
6. Shown in Figure 6(a) is the magnetization eurve of a DC machine at om 200 rad/s. Find the speed wm when the machine is configured as a shunt connection motor as shown in Figure 6(b) with a torque Tn 100 Nm added, and calculate the power developed by the motor. 15 points) Ea(v) 120 100-- ahn = 200 rad/s =0.2 Ω 8o - 100 n L.a Vin 100 v 60 40 20 Figure 6 6. Shown in Figure 6(a)...
42. For the motor, load, and torque-speed curve shown in Figure P2.28, find the transfer function, G(s) = 0_(s)/E.s). [Section: 2.8] 801 = kg-m) N=50 , N = 150 D = 8N-m-/rad AV = 18 kg-m D2 = 36 N-m-s/rad 2 1 (N-m) Enhanében Enhancer 150 (rad/s) FIGURE P2.28
A weight of 500 kg is being lifted up at a uniform speed of 1.5 M/S by a winch driven by a motor running at a speed of 1000 rpm. The moments of inertia pf the motor and winch are 0.3 and 0.3 kg-m respectively. Calculate the motor torque and the equivalent moment of inertia referred to the motor shaft. In the absence of weight, motor develops a torque of 100 N-m when running at 1000 rpm.