The vertical ground reaction force acting under a runner’s foot is 1500 N, while the frictional force is 700 N acting forward. What is the resultant of these two forces? What is the angle of the resultant force with respect to horizontal?
The vertical ground reaction force acting under a runner’s foot is 1500 N, while the frictional...
At early stance phase, a runner’s ground reaction force is 1500 N at a 55-degree angle with respect to the ground. If the runner’s mass is 90 kg, what are their accelerations ax and ay?
The ground reaction force acting on Carter during his long jump is 4500N acting forward and upward at an angle of 78 degrees from horizontal. Carter’s mass is 70kg. Other than gravity, this is the only external force acting on Carter A. What is the vertical component of this ground reaction force? B. What is the horizontal component of this ground reaction force? C. How big is the net force, the sum of all the external forces, acting on Carter?...
Daisy walks across a force platform, and the forces exerted by her foot during a step are recorded. The peak vertical reaction force is 1200N (this force acts upward on daisy). At the same instant, the braking frictional force is 200N (this force acts backward on daisy) A.) how large is the resultant of these forces? B.) what is the direction of the resultant force? n of the resultant forcé 200 N
Vector A is a force of 400 N acting at an angle of 0° from horizontal. Vector B is a force of 300 N acting at an angle of 120° from horizontal. Calculate the resultant of these two vectors.
The 5.6 N weight is in equilibrium under the influence of the three forces acting on it. The F force acts from above on the left at an angle of α with the horizontal. The 5.3 N force acts from above on the right at an angle of 62◦with the horizontal. The force 5.6 N acts straight down. A. What is the magnitude of the force F? Answer in units of N. B. What is the angle α of the...
A shot putter exerts a force of 100N acting forward and upward on a 40N shot put at an angle of 60° from horizontal. Other than gravity, the weight of the shot put (40N) is the only external force acting on it. a. What was the vertical component of this force? b. What is the horizontal component of this force? c. How big was the NET force (sum of all external forces) acting on the shot put? (remember gravity is...
The 3.4 N weight is in equilibrium under the influence of the three forces acting on it. The F force acts from above on the left at an angle of α with the horizontal. The 6 N force acts from above on the right at an angle of 47◦ with the horizontal. The force 3.4 N acts straight down. Note: F, α are not to scale. a) What is the magnitude of the force F? Answer in units of N....
What is the X-component of a force 27 N acting at an angle of 58 degrees. Question 6 2 pts If a resultant of two forces in the experiment comes to 300 g at 30 degrees, what is the magnitude and direction of the Equilibrant? (give answer in grams, and the angle as counterclockwise from the X-axis)
a) The horizontal force(s) (direction and magnitude) acting on the gate per unit width and draw the pressure distribution diagram(s) [6 marks] b) The vertical force(s) acting on the gate per unit width (Include direction and magnitude). [6 marks] c) If the gate is 5 m long (into the page), calculate the magnitude, direction and angle of the resultant hydrostatic force acting on the gate. [7 marks] d) The net horizontal force acting on the dam per unit width. Include...
A 55-kg gymnast applies a vertical ground reaction force of 1,100 N at 0.17 m behind the center of mass during a forward somersault. Assume she is facing the right. What is the torque generated about the center of mass? a. 279 N-m b. −92 N-m c. 187 N-m d. −187 N-m