Question

"Customers arrive at a suburban ticket outlet at the rate of 14 per hour on Monday...

"Customers arrive at a suburban ticket outlet at the rate of 14 per hour on Monday mornings (exponential interarrival times). Selling the tickets and providing general information takes an average of 3 minutes per customer and varies exponentially. There is 1 ticket agent on duty on Mondays. How many minutes does the average customer spend in the system?"

a). 7

b). 8

c). 9

d). 10

e). 11

0 0
Add a comment Improve this question Transcribed image text
Answer #1

The correct answer is A) 7

Given:

Λ mean rate of arrival = 14

µ: mean service rate = 60/3 = 20

Wq : Mean wait in the queue: Λ/ µ(µ- Λ)

Wq => 14/20(20-14) = > 14/120 = > 0.116 => 0.166*60 = 7 Minutes

Add a comment
Know the answer?
Add Answer to:
"Customers arrive at a suburban ticket outlet at the rate of 14 per hour on Monday...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Customers arrive at a suburban ticket outlet at the rate of 14 per hour on Monday...

    Customers arrive at a suburban ticket outlet at the rate of 14 per hour on Monday mornings (exponential interarrival times). Selling the tickets and providing general information takes an average of 3 minutes per customer, and varies exponentially. There is 1 ticket agent on duty on Mondays. How many minutes does the average customer spend in the system? Group of answer choices 7 8 9 10 11

  • Customers arrive at a suburban ticket outlet at the rate of 4 per hour on Monday...

    Customers arrive at a suburban ticket outlet at the rate of 4 per hour on Monday mornings. This can be described by a Poisson distribution. Selling the tickets and providing general information takes an average of 12 minutes per customer, and varies exponentially. There is 1 ticket agent on duty on Mondays. Determine the System Utilization Question 12 options: .8 1.6 .4 .88 None of the Above Question 13 (1.5 points) Customers arrive at a suburban ticket outlet at the...

  • Customers arrive at a suburban ticket outlet at the rate of 10 per hour on Monday...

    Customers arrive at a suburban ticket outlet at the rate of 10 per hour on Monday mornings. This can be described by a Poisson distribution. Selling the tickets and providing general information takes an average of 5 minutes per customer, and varies exponentially. There is 1 ticket agent on duty on Mondays. Determine the System Utilization

  • Waiting lines Customers walk in at random to a deli. The interarrival times are exponentially dis...

    Waiting lines Customers walk in at random to a deli. The interarrival times are exponentially distributed with an average of 5 minutes. The deli prepares one order at a time. The order preparation times are exponentially distributed with an average of 3 minutes. 13. What kind of waiting line model is appropriate for the deli? 14. What is the utilization? 15. What is the total amount of time a customer would expect to spend at the deli (from walking in...

  • Customers arrive at a local ATM at an average rate of 15 per hour. Assume the...

    Customers arrive at a local ATM at an average rate of 15 per hour. Assume the time between arrivals follows the exponential probability distribution. Determine the probability that the next customer will arrive in the following time frames. ​a) What is the probability that the next customer will arrive within the next 5 ​minutes? ​b) What is the probability that the next customer will arrive in more than 8 ​minutes? ​c) What is the probability that the next customer will...

  • Customers arrive at Rich Dunn's Styling Shop at a rate of 2 per hour, distributed in...

    Customers arrive at Rich Dunn's Styling Shop at a rate of 2 per hour, distributed in a Poisson fashion. Service times follow a negative exponential distribution, and Rich can perform an average of 5 haircuts per hour. customers (round your response to two decimal places). a) The average number of customers waiting for haircuts = customers (round your response to two decimal places). b) The average number of customers in the shop = c) The average time a customer waits...

  • Customers arrive at the coffee shop in Bilkent FBA atrium, with a mean rate of 80 per hour (assume Poisson). It takes the barista, on average 30 seconds per cup of coffee (assume Exponential). Assume...

    Customers arrive at the coffee shop in Bilkent FBA atrium, with a mean rate of 80 per hour (assume Poisson). It takes the barista, on average 30 seconds per cup of coffee (assume Exponential). Assume also that each customer buys only one cup. Determine: (a) The average number of customers waiting in line. (b) The average time customers spend in the system. (c) The average number of customers in the system. (d) The probability that a customer will not have...

  • customers arrive at an average of 30 per hour. A single server in the store serves...

    customers arrive at an average of 30 per hour. A single server in the store serves customers, taking 1.5 minutes on average to serve each customer. Inter-arrival times and service times follow the exponential distribution. What is the expected fraction of time that the server will be busy? On average, how many people will there be in the store? On average, how long will someone be in the store? What is the probability that there will be more than 2...

  • What is the probability that exactly 4 customers will arrive in 1 hour, when the mean...

    What is the probability that exactly 4 customers will arrive in 1 hour, when the mean arrival rate is 3 customers per hour, and interarrival times are exponentially distributed? a 0.3528 b 0.1847 c 0.1680 d 0.8153 e 0.6472

  • **LOOKING FOR FORMULAS, ANSWERS PROVIDED. Problem-1: At a single-phase, multiple-channel service facility, customers arrive randomly. Statistical...

    **LOOKING FOR FORMULAS, ANSWERS PROVIDED. Problem-1: At a single-phase, multiple-channel service facility, customers arrive randomly. Statistical analysis of past data shows that the interarrival time has a mean of 20 minutes and a standard deviation of 4 minutes. The service time per customer has a mean of 15 minutes and a standard deviation of 5 minutes. The waiting cost is $200 per customer per hour. The server cost is $25 per server per hour. Assume general probability distribution and no...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT