A solution is prepared by mixing 4.32 mol of acetone with 1.45 mol of cyclohexane at 30°C. Calculate the Xacetone and Xcyclohexane in the vapor above the solution. P°acetone = 229.5 torr and P°cyclohexane = 97.6 torr.
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A solution is prepared by mixing 4.32 mol of acetone with 1.45 mol of cyclohexane at...
05 Question (12 points) A solution is prepared by mixing 2.92 mol of acetone with 1.45 mol of cyclohexane at 30°C. 3rd attempt O See Hin Calculate the Xacetone and Xcyclohexane in the vapor above the solution. P acetone 229.5 torr and Pcycloexane 97.6 torr 229.5 torr and Pcyclohexane 97.6 torr e Xacetone in the vapor 00255 Xcyclohexane in the vapor0.1745
9) A solution is composed of 1.10 mol cyclohexane (Po=97.6 torr) and 2.60 mol acetone (Po =229.5 torr). What is the total vapor pressure Ptotal above this solution?
A. If 0.420 mol of a nonvolatile nonelectrolyte are dissolved in 3.10 mol of water, what is the vapor pressure PH2O of the resulting solution? The vapor pressure of pure water is 23.8 torr at 25 ∘C . B. A solution is composed of 1.80 mol cyclohexane (P∘cy=97.6 torr) and 2.30 mol acetone (P∘ac=229.5 torr). What is the total vapor pressure Ptotal above this solution? C. As you saw in Part B, the vapor above the cyclohexane-acetone solution is composed of...
PART A If 0.720 mol of a nonvolatile nonelectrolyte are dissolved in 3.20 mol of water, what is the vapor pressure PH2O of the resulting solution? The vapor pressure of pure water is 23.8 torr at 25 ∘C . PART B A solution is composed of 1.90 mol cyclohexane (P∘cy=97.6 torr) and 2.30 mol acetone (P∘ac=229.5 torr). What is the total vapor pressure Ptotal above this solution?
If 0.720 molmol of a nonvolatile nonelectrolyte are dissolved in 3.70 molmol of water, what is the vapor pressure PH2OPH2O of the resulting solution? The vapor pressure of pure water is 23.8 torrtorr at 25 ∘C∘C . Express your answer with the appropriate units A solution is composed of 1.60 molmol cyclohexane (P∘cy=97.6 torrPcy∘=97.6 torr) and 2.90 molmol acetone (P∘ac=229.5 torrPac∘=229.5 torr). What is the total vapor pressure PtotalPtotal above this solution? Express your answer with the appropriate units
A solution is prepared by mixing 44.0 g of acetone (C3H6O) and 297.2g of chloroform (CHCl3). The vapor pressures of pure acetone and pure chloroform at 35 degrees C are 345 and 293 torr. If this is an ideal solution, what is the vapor pressure, in torr, of the solution at 35 degrees C?
4) 440 pnts) A solution is prepared by mixing some volume of methanol (MM = 32.04 g/mol, d=0.792 g/mL, p = 94.0 torr) and acetone (MM=58.07 g/mol, d=0.784 g/mL, Pº = 240. torr) at room temperature. Assuming that the volumes additive on mixing. a) What is the mole fraction of acetone and methanol in solution if the number of acetone and methanol gas molecules above the solution are equal to one another? Assume ideal solution behavior.
8) Hexane (P 152 torr ) and cyclohexane (P 97.6 torr) form an ideal solution. At some solution concentration the vapor above the solution is comprised of hexane:cyclohexane molecules in a 1:3 ratio. What is the composition of the solution in mole percentages?
A solution is prepared by mixing 75 g of benzene (C6H6) with 25 g of toluene (C7H8). Use the following data to determine the vapor pressure of this solution at 20C. (Hint: Calculate the vapor pressure of each substance in solution separately, then add them together to get the total vapor pressure of the solution.) Vapor Pressure at 20C (torr) Benzene 75 Toluene 22 a. 35 torr b. 87 torr c. 63 torr d. 71 torr e. 49 torr
Calculate the total vapor pressure of a solution made by mixing 0.500 mol of ether (C4H10O) with 0.200 mol of ethanol (C2H6O) at 20 °C. At 20 oC, Po for ether = 440 torr, Po for ethanol = 332 torr