5. For the reaction: PCl5(g) ⇌ PCl3(g) + Cl2(g), what will happen when the temperature is increased? (Hint: Do you think a decomposition reaction is endothermic or exothermic?)
A decomposition reaction is an endothermic reaction since the reactant needs energy to break its bonds.
Thus it takes energy to break the bonds between its molecules, making decomposition reaction endothermic.
When the temperature is increased for an endothermic reaction, there is more heat, therefore an endothermic reaction proceeds in the forward direction.
Therefore more products are formed.
5. For the reaction: PCl5(g) ⇌ PCl3(g) + Cl2(g), what will happen when the temperature is...
The dissociation of PCl5(g) to PCl3(g) and Cl2(g) is an endothermic reaction. PCl5(g) PCl3(g) + Cl2(g) What is the effect on the position of equilibrium of each of the following changes? a) Compressing the gaseous mixture _________________________________ b) Decreasing the temperature _________________________________ c) Adding Cl2(g) to the equilibrium mixture __________________________________ d) Removing PCl5 (g) from the equilibrium mixture __________________________________
PCl5 decompose into PCl3 and Cl2 when heated. A 0.72-mol sample of PCl5 is put into a 1.00-L vessel and heated. At equilibrium, the vessel contains 0.40 mol of PCl3(g) and 0.40 mol of Cl2(g). Calculate the value of the equilibrium constant for the decomposition this decomposition reaction at this temperature.
QUESTION 1 In the reaction: PCl5 <----> PCl3 + Cl2 When the amount of PCl5 is increased, which of the following will occur? Check all that apply, deductions for incorrect choices. 1. the reaction will move to the right 2. The reaction will move to the left 3. PCl3 will increase 4. PCl3 will decrease 5. Cl2 will increase 6. Cl2 will decrease QUESTION 2 In the reaction: PCl5 <----> PCl3 + Cl2 When the amount of PCl3 is increased,...
For the reaction PCl3 + Cl2 --> (reversible) PCl5 + heat What will happen to the amount of PCl5 created if heat is removed? What symbol is missing in the following nuclear equation: 2311Na + 21H --> __?__ + 11H HELP!!! Can't get these questions right!
What are the equilibrium partial pressures of PCl3, Cl2, and PCl5, respectively?Express your answers numerically in atmospheres with three digits after the decimal point, separated by commas.An Equilibrium Study: Phosphorus Trichloride/Phosphorus Pentachloride EquilibriumFor the exothermic reactionPCl3(g)+Cl2(g)→PCl5(g)Kp = 0.180 at a certain temperature.A flask is charged with 0.500 atm PCl3 , 0.500 atm Cl2, and 0.300atm PCl5 at this temperature.
Phosphorous pentachloride decomposes according to the reaction PCl5(g)↽−−⇀PCl3(g)+Cl2(g)PCl5(g)↽−−⇀PCl3(g)+Cl2(g) A 13.5 g13.5 g sample of PCl5PCl5 is added to a sealed 1.50 L1.50 L flask and the reaction is allowed to come to equilibrium at a constant temperature. At equilibrium, 34.8%34.8% of the PCl5PCl5 remains. What is the equilibrium constant, ?cKc , for the reaction? ?c=Kc=
In the equation below, PCl3(g) + Cl2(g) « PCl5(g) the forward reaction is first order in both PCl3 and Cl2 and the reverse reaction is first order in PCl5. (a) Suppose that 2 moles of PCl3 and 1 mole of Cl2 are mixed in a closed 1.0 L container at constant temperature. Draw a graph that shows how the concentrations of PCl3, Cl2, and PCl5 change with time until after equilibrium has been firmly established. Indicate the numerical values on...
Consider the reaction: PCl5 (g) ⇔ PCl3 (g) + Cl2 (g) The initial concentration of PCl5 is 0.40 M and the equilibrium concentration of PCl3 is 0.33 M. Calculate the equilibrium constant Kc.
The equilibrium constant Kp for the reaction PCl5(g) <---> PCl3(g) + Cl2(g) is 1.15 at 25 degrees Celsius. The reaction starts with a mixture of 0.177 atm PCl5, 0.223 atm PCl3, and 0.111 atm Cl2. When this mixture comes to equilibrium at 25 degrees Celsius, what are the equilibrium pressures of each component?
Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g)?c=0.0420 PCl 5 ( g ) ↽ − − ⇀ PCl 3 ( g ) + Cl 2 ( g ) K c = 0.0420 The concentrations of the products at equilibrium are [PCl3]=0.270 M [ PCl 3 ] = 0.270 M and [Cl2]=0.180 M [ Cl 2 ] = 0.180 M . What is the concentration of the reactant, PCl5 PCl 5 , at equilibrium? [PCl5]= [ PCl 5 ] =