For the reaction
PCl3 + Cl2 --> (reversible) PCl5 + heat
What will happen to the amount of PCl5 created if heat is removed?
What symbol is missing in the following nuclear equation:
2311Na + 21H --> __?__ + 11H
HELP!!! Can't get these questions right!
Given
PCl3 + Cl2 <==> PCl5 + heat
According to LeChatelier's principle
As heat is removed equilibrium is distributed so to attain equilibrium the change occurs reverse to that of original change
So
By removing heat the equilibrium is distributed in the product side so now more heat is produced by the conversion of reactants to products so that along with heat concentration of PCl5 also increases
A new equilibrium will be established
Hence amount of PCl5 increases
----------------------------------------------------------
11Na23 + 1H2 ==> ____ + 1H1
So
Sum of protons in the left side is 11+1 = 12 so
Sum of protons in the right side should also be 12 (11 + 1)
Also
Sum of mass number in the left side is 23+2 =25 so
Sum of mass number in the right side should also be 25 (24 + 1)
Thus the missing symbol has protons 11 and mass number 24
Which is 11Na24
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