Question

A climatologist is measuring rainfall for the month of June in three Canadian cities. Records from...

A climatologist is measuring rainfall for the month of June in three Canadian cities. Records from several years are used for each city. Use this data to test the hypothesis that mean rainfall is the same for June in all three cities.

Summary
Groups Count Sum Average Variance
Victoria 10 144 14.4 0.9333
Calgary 3 37 12.3333 4.3333
Regina 4 47 11.75 4.25
ANOVA Table
Source of Variation SS df MS F
Between Groups 24.301 2 12.1505 5.7051
Within Groups 29.8167 14 2.1298
Total 54.1176 16


a) What is the critical value at the 0.05 significance level?

Critical value: 0

b) What do you conclude (using this significance level)?
The mean rainfall is the same for each city
The mean rainfall is not the same for each city
No conclusion can be drawn
0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A climatologist is measuring rainfall for the month of June in three Canadian cities. Records from...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • a. Given the following information obtained from three normally distributed populations, construct an ANOVA table. (Round...

    a. Given the following information obtained from three normally distributed populations, construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, and "P' to 3 decimal places.) SSTR = 220.7; SSE = 2,252.2; c = 3; ni = n2 = n3 = 8 ANOVA Source of Variation SS df MS F p-value Between Groups 0.375 Within Groups 0.00 0 Total b. At the 1% significance level,...

  • For Questions 11-15, consider the following: The Human Resource Manager of a large insurance company wishes...

    For Questions 11-15, consider the following: The Human Resource Manager of a large insurance company wishes to evaluate the leadership qualities of 3 manager groups-supervisors, mid-level managers and upper-level managers. 12 people from each management level were sampled. Is there a difference on the average of the leadership scores for the three groups? Part of the leadership scores (higher is better) and ANOVA table are as follows: Supervisor Mid-Manager Upper-Manager 33 29 32 43 36 39 34 32 40 29...

  • The Human Resource Manager of a large insurance company wishes to evaluate the leadership qualities of...

    The Human Resource Manager of a large insurance company wishes to evaluate the leadership qualities of 3 manager groups- supervisors, mid-level managers and upper-level managers. 12 people from each management level were sampled. Is there a difference on the average of the leadership scores for the three groups? Part of the leadership scores (higher is better) and ANOVA table are as follows: Supervisor Mid- Manager Upper-Manager 33 29 32 43 36 39 34 32 40 29 36 46 ANOVA TABLE...

  • In a test of weight loss programs, 120 subjects were divided such that 40 subjects followed...

    In a test of weight loss programs, 120 subjects were divided such that 40 subjects followed each of 3 diets. Each was weighed a year after starting the diet and the results are in the ANOVA table below. Use a 0.05 significance level to test the claim that the mean weight loss is the same for the different diets. Source of Variation SS df MS F P-value Fcrit Between Groups 91.990 2 45.99487 1.3743 0.257070 3.073763 Within Groups 3915.738 117...

  • Score: vor 12.1.5 Question Help In a test of weight loss programs, 111 subjects were divided...

    Score: vor 12.1.5 Question Help In a test of weight loss programs, 111 subjects were divided such that 37 subjects followed ench of 3 diets. Each was weighed a year after starting the diet and the results are in the ANOVA table below. Use a 0.025 significance level to test the claim that the mean weight loss is the same for the different diets. Source of Variation SS df MS F P-value Forff Between Groups 202.462 2 101 23117 3.2046...

  • The data in the table were collected from randomly selected flights at airports in three cities...

    The data in the table were collected from randomly selected flights at airports in three cities and indicate the number of minutes that each plane was behind schedule at its departure. City 1 | City 2 | City 3 29 14 a" Perform a one-way ANOVA using α:005 to determine if there is a difference in the average lateness of flights from these three airports. b. Perform a multiple comparison test to determine which pairs are different using α: 0.05....

  • An experiment has a single factor with three groups and five values in each group. In...

    An experiment has a single factor with three groups and five values in each group. In determining the among-group variation, there are 2 degrees of freedom. In determining the within-group variation, there are 12 degrees of freedom. In determining the total variation, there are 14 degrees of freedom. Also, note that SSA 36, SSW 108, SST 144, MSA = 18, MSW 9, and FSTAT = 2. Complete parts (a) through (d). Click here to view page 1 of the F...

  • 5) A group of paramedics believes that the number of calls they receive is the same...

    5) A group of paramedics believes that the number of calls they receive is the same for each of their three shifts (morning, afternoon, and evening). To test their claim, they record the number of calls during each shift for seven days. The results of an EXCEL One-Way ANOVA test on the data is shown below. Use a 0.01 significance level to test the claim that the mean number of calls is the same for each shift. (a) State the...

  • 5) A group of paramedics believes that the number of calls they receive is the same...

    5) A group of paramedics believes that the number of calls they receive is the same for each of their three shifts (morning, afternoon, and evening). To test their claim, they record the number of calls during each shift for seven days. The results of an EXCEL One-Way ANOVA test on the data is shown below. Use a 0.01 significance level to test the claim that the mean number of calls is the same for each shift. (a) State the...

  • You can assume that the data followed all three assumptions for ANOVA analysis, namely, independence, equal...

    You can assume that the data followed all three assumptions for ANOVA analysis, namely, independence, equal variance, and normality. Placebo Dose2 Dose5 4.3 3.7 1.3 9.1 3.5 1 6.1 5.2 0.7 4.7 9.3 1.2 4.1 6.7 1.3 7.8 5.2 1.6 5.7 4.1 2.4 5.8 5.3 1.9 Here is my ANOVA table SUMMARY Groups Count Mean Std Dev Placebo 8 5.95 1.74 Dose2 8 5.375 1.90 Dose5 8 1.425 0.53 Results Source of Variation SS df MS F P-value Between 97.41...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT