An unknown acid salt was dissolved in water and titrated with 0.105 M NaOH. If 1.20...
An unknown acid salt was dissolved in water and titrated with 0.105 M NaOH. If 1.20 grams of the salt were dissolved and it took 120 mL to reach the equivalence point, what is the unknown?
( )NaF
( ) NH4Cl
( ) (CH3)3NHCl
( ) NaHCO3
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An unknown acid salt was dissolved in water and titrated with
0.105 M NaOH. If 1.20...
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A 1.20 gram sample of an unknown monoprotic acid is dissolved in 25.0 mL of water and titrated with a a 0.485 M aqucous potassium hydroxide solution. It is observed that after 7.33 milliliters of potassium hydroxide have been added, the pH is 4.515 and that an additional 13.3 mL of the potassium hydroxide solution is required to reach the equivalence point. (1) What is the molecular weight of the acid? (2) What is the value of K, for the...
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A sample of 0.2140 grams of an unknown monoprotic weak acid was dissolved in 25.0mL of...
A sample of 0.2140 grams of an unknown monoprotic weak acid was dissolved in 25.0mL of water and titrated with 0.0950M NaOH. The acid required 15.50mL of NaOH to reach the equivalence point. What is the molar mass of the unknown acid?
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A sample of 0.2140 g of an unknown monoprotic acid was dissolved in 25.0 mL of...
A sample of 0.2140 g of an unknown monoprotic acid was dissolved in 25.0 mL of water and titrated with 0.0950 M NaOH. The titration required 30.0 mL of base to reach the equivalence point, at which point the pH was 8.68. a) What is the molecular weight of the acid? b) What is the pKa of the acid?
you titrated an unknown acid with 0.0925 M NaOH, 0.6201g of the unknown acid was placed into an Erlenmeyer flask with10...
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The student dissolved 2.050 grams of acid in 50 mL of distilled water. He then titrated...
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