Question

DESCRIPTIVE STATISTICS: Create a table of descriptive statistics with an appropriate tabular format. See the Output...

  1. DESCRIPTIVE STATISTICS: Create a table of descriptive statistics with an appropriate tabular format. See the Output A[2 pt].

  1. STATISTICAL RESULTS: Report and statistically interpret the results with an appropriate tabular format and text. See the Output B. [6 pt]

  1. DISCUSSION: Discuss what the results imply. [2 pt]

Output A. Descriptive statistics

Statistics

Exam Performance (%)

Exam Anxiety

N

Valid

103

103

Missing

0

0

Mean

56.57

74.3437

Median

60.00

79.0440

Std. Deviation

25.941

17.18186

Minimum

2

1.00

Maximum

100

100.00

Output B. Simple Linear Regression Results

Correlations

Exam Performance (%)

Exam Anxiety

Pearson Correlation

Exam Performance (%)

1.000

-.441

Exam Anxiety

-.441

1.000

Sig. (1-tailed)

Exam Performance (%)

.

.000

Exam Anxiety

.000

.

N

Exam Performance (%)

103

103

Exam Anxiety

103

103

Model Summary

Model

R

R Square

Adjusted R Square

Std. Error of the Estimate

1

.441a

.194

.186

23.397

a. Predictors: (Constant), Exam Anxiety

Coefficientsa

Model

Unstandardized Coefficients

Standardized Coefficients

t

Sig.

95.0% Confidence Interval for B

B

Std. Error

Beta

Lower Bound

Upper Bound

1

(Constant)

106.071

10.285

10.313

.000

85.667

126.474

Exam Anxiety

-.666

.135

-.441

-4.938

.000

-.933

-.398

a. Dependent Variable: Exam Performance (%)

0 0
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Answer #1

From Output B we can say that the correlation coefficient between Anxiety and Exam performance is -0.441 which means more the anxiety less the exam performance (%)

Also P value= 0.000 which is less than the level of significance (0.05) therefore significant hence we can conclude that there is correlation between anxiety and exam Performance (%)

Also from third table of Output B the regression equation is

y(hat)= 106.071+ -0.666*Exam anxiety

This equation means for a unit increase in anxiety there is down of 0.666 scores percentage in exam.

If we do testing of regression coefficients ( and ) we will find that p value is 0.000 which is less than the level of significance (0.05) therefore SIGNIFICANT.

R square= 0.194 which indicates that the model explains 19.4% of the variability of the response data around its mean.

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