Question

6. Interpreting statistical software output in regression Aa Aa Suppose you work in the admissions department of a small libeCoefficientsa Standardized Coefficients Beta Unstandardized Coefficients Model Std Error 0.4985 0.000271 Two-Tailed Sig 0.000

6. Interpreting statistical software output in regression Aa Aa Suppose you work in the admissions department of a small liberal arts college. You wonder if you can predict students' college grade point averages (GPAs) by their SAT scores. You randomly select 50 recent graduates and collect their SAT scores and college GPAs. You use a statistical software package to run a regression predicting college GPA from SAT score. Use the following output to answer the questions that follovw Descriptive Statistics Mean 3.064 1816 Std Deviation 0.5574 280.20 College GPA SAT score 50 50 Model Summary Adjusted R Square 0.0884 Std Error of the Estimate 0.5322 Model R Square 0.327a 0.107 a. Predictors (constant): SAT score ANOVAa Sum of Squares Model df Mean Square 1.6295 0.28324 Two-Tailed Sig 0.0204b 1 Regression 1.6295 13.596 15.225 5.7530 Residual Total a. Dependent variable: college GPA b. Independent variables (constant): SAT score 48 49
Coefficientsa Standardized Coefficients Beta Unstandardized Coefficients Model Std Error 0.4985 0.000271 Two-Tailed Sig 0.0004 0.0204 1 (Constant) 1.8821 3.7759 SAT score 0.000651 0.327 2.3985 a. Dependent variable: college GPA , where Ý is the predicted value of The regression equation is Y- and X is the value of The Pearson correlation between SAT score and college GPA is You believe there is a linear relationship between SAT score and college GPA. You conduct a hypothesis test with the null hypothesis Ho: β1 = 0 versus the alternative hypothesis H1: β1キ0. Based on these results, with a significance level of a.05, you are linearly related reject the null hypothesis. You conclude that SAT score and college GPA
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ans:

Regression equation is:

Y'=0.000651 X+1.8821

Where Y' is the predicted value of college GPA and X is the value of SAT score.

Correlation between college GPA and SAT score is 0.327

Test statistic:

t=2.3985

p-value=0.0204

As,p-value<0.05,we should reject the null hypothesis.

You can conclude that SAT score and college GPA are linearly related.

Add a comment
Know the answer?
Add Answer to:
6. Interpreting statistical software output in regression Aa Aa Suppose you work in the admission...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Use the following for questions 21-27 The following is software output from a regression analysis on...

    Use the following for questions 21-27 The following is software output from a regression analysis on the relationship between Math SAT score and the Computer Science GPA for college graduates with a BA degree in Computer Science. The data is from 102 randomly selected students at a state university Math SAT Scores and Computer Science GPA for Computer Science BA Graduates Residuals 550 600 650 700 550 600 650 700 Math SAT Scores Math SAT Scores Regression Output Estimate Std....

  • A researcher uses two regression models to seek answers to two research questions. These models a...

    A researcher uses two regression models to seek answers to two research questions. These models are: Y1 = Bo1 + B11X1 Y2 = Bo2 + B12X1 + B22X12 Test the null hypotheses for both models. Use the results of your analyses to recommend an appropriate model. In each of the above two cases, state your null and alternative hypotheses, decision criteria, decision and conclusion. The level of significance is 5%. The data for this study are presented in the table...

  • Models 1-7 are below Part C: Select one model you would use to explain reading ability.,Then use that model to find the 95% confidence interval estimate for the mean reading ability 95% p...

    Models 1-7 are below Part C: Select one model you would use to explain reading ability.,Then use that model to find the 95% confidence interval estimate for the mean reading ability 95% prediction interval for reading ability When age 6, mem span 4.2 and ig 91. Regression [DataSetll C:\Usersn.little5773 Downloads\child data.sav Variables Entered/Removed Variables Entered Variables Removed Method Model Enter age a. Dependent Variable: reading ability b. All requested variables entered. Model Summary Adjusted R Square Std. Error o R...

  • Investigate the relationship between the respondent’s education (EDUC) and the education received...

    Investigate the relationship between the respondent’s education (EDUC) and the education received by his or her father and mother (PAEDUC and MAEDUC, respectively). Calculate the correlation coefficient, the coefficient of determination, and the regression equation predicting the respondent’s education with father’s education only. Interpret your results. Determine the multiple correlation coefficient, the multiple coefficient of determination, and the regression equation predicting the respondent’s education with father’s and mother’s education. Interpret your results. Did taking into account the respondent’s mother’s education...

  • DISPLAY A Descriptives Descriptive Statistics N Minimum Maximum Mean Std. Deviation 1.376 72.673 ...

    DISPLAY A Descriptives Descriptive Statistics N Minimum Maximum Mean Std. Deviation 1.376 72.673 EXPENDITURE 48 3.656 9.774 5.946 SAT 48 854.000 1107.000 970.563 Valid N (listwise) 48 Model Summary Model R R Square Adjusted R Std. Error of Square the Estimate 65.492 453 205 188 a Predictors: (Constant), EXPENDITURE ANOVA Model F Sig. Sum of df Mean Square Squares 50920.77 11.872 0.001 4289.197 1 Regression 50920.77 1 Residual 197303.00 46 Total 248223.80 47 a Predictors: (Constant), EXPENDITURE b Dependent Variable:...

  • 43 college students 44% male, 56% female Students reported on the number of hours spent studying...

    43 college students 44% male, 56% female Students reported on the number of hours spent studying per week (0-40 hours), their life satisfaction (scale from 0-100), degree of stress they experienced over the last month (scale 0-5), and completed an IQ test (40-160). Students also reported their gender (1=male, 2=female) and cumulative GPA. For the statistical analysis performed, you need to provide responses to two questions: What type of statistical analysis was used to examine what kind of research question?...

  • 43 college students 44% male, 56% female Students reported on the number of hours spent studying...

    43 college students 44% male, 56% female Students reported on the number of hours spent studying per week (0-40 hours), their life satisfaction (scale from 0-100), degree of stress they experienced over the last month (scale 0-5), and completed an IQ test (40-160). Students also reported their gender (1=male, 2=female) and cumulative GPA. For the statistical analysis performed, you need to provide responses to two questions: What type of statistical analysis was used to examine what kind of research question?...

  • The following questions refer to the output shown below. Researchers used temperature to predict failure time...

    The following questions refer to the output shown below. Researchers used temperature to predict failure time for a superconductive material with the following a. Write the regression equation based on the results shown below. b. Assess the model utility. linear model: yˆ = β0 + β1xtemp Write the regression equation based on the results shown below. Would you recommend the model? Why or why not? Model Summary Adjusted R Model R R Square Square .918a .843 .835 a. Predictors: (Constant),...

  • Regression Variables Entered/Removeda Model Variables Entered Variables Removed Method 1 Warranty_Yearsb . Enter a. Dependent Variable:...

    Regression Variables Entered/Removeda Model Variables Entered Variables Removed Method 1 Warranty_Yearsb . Enter a. Dependent Variable: Number_of_people_mentioned b. All requested variables entered. Model Summary Model R R Square Adjusted R Square Std. Error of the Estimate 1 .503a .253 .251 .95930 a. Predictors: (Constant), Warranty_Years ANOVAa Model Sum of Squares df Mean Square F Sig. 1 Regression 80.590 1 80.590 87.574 .000b Residual 237.425 258 .920 Total 318.015 259 a. Dependent Variable: Number_of_people_mentioned b. Predictors: (Constant), Warranty_Years Coefficientsa Model Unstandardized...

  • Linear regression analysis of the data revealed the following: Model Summary Model R R Square Adjusted...

    Linear regression analysis of the data revealed the following: Model Summary Model R R Square Adjusted R Square Std. Error of the Estimate 1 .695a .483 .478 13.02473 a. Predictors: (Constant), exercise, gender, subject's age, depressed state of mind ANOVAa Model Sum of Squares df Mean Square F Sig. 1 Regression 65230.870 4 16307.718 96.129 .000b Residual 69893.149 412 169.644 Total 135124.019 416 a. Dependent Variable: Life Purpose and Satisfaction b. Predictors: (Constant), exercise, gender, subject's age, depressed state of...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT