An electron having a kinetic energy of 10 GeV makes a head-on collision with a positron having the same energy. The collision produces two muons (mc2 = 105.7 MeV) moving in opposite directions. Find the kinetic energy and velocity of each muon.
An electron having a kinetic energy of 10 GeV makes a head-on collision with a positron...
An electron (rest mass me) of energy E makes a head-on collision with a positron (positron is electron’s antiparticle, it has the same mass as electron, but opposite charge) In collision the two particles annihilate each other and are replaces by two photons (γ rays) of equal energy, each traveling at equal angles θ with electron’s direction of motion. Find 1. The energy of each photon. 2. The momentum p of each photon. 3. The angle θ. Problem 3. Electron-positron...
An electron and a positron, each moving at 3.0 x 10^5m/s, collide head on, disappear, and produce two photons moving in opposite directions, each with the same energy and momentum. Determine the energy and momentum of each photon (show your units)
the annihilation of an electron and a positron, each with negligible kinetic energy, results in the production of two photons with the same energy. (a) Determine the energy of each photon in MeV. MeV (b) Determine the wavelength of each photon. m
You may assume the proton mass = 1 GeV and the electron and muon masses are negligible. I would appreciate an answer to part two! In an experiment two beams of protons with the same energy are fired at each other. Particle detectors surround the interaction point. One unusual event is recorded which contains one electron and two muons. It is hypothesized that these could arise from the decay of a hitherto unknown particle, the 'X'. The energy and momentum...
An electron-positron pair is produced by a 2.85 MeV photon. What is the kinetic energy of the positron if the kinetic energy of the electron is 1.219 MeV? Use the following Joules-to-electron-Volts conversion 1eV = 1.602 × 10-19 J. The rest mass of an electron is 9.11 × 10-31 kg Please answer in MeV
Particle Physics Let's do a little particle physics. Back in the '9os there was a large electron-positron collider at CERN in Geneva, Switzerland, called the "Large electron-positron collider," or LEP for short. (This collider was broken down and rebuilt into an even larger one that runs to this day, called the "Large hadron collider" or LHC.) It was LEP that discovered the W and Z bosons, which mediate weak nuclear processes like the beta decay of free neutrons Anyway, near...
An electron-positron pair is produced by a 2.30 MeV photon. What is the kinetic energy of the positron if the kinetic energy of the electron is 0.958 MeV? Use the following Joules-to-electron-Volts conversion 1eV = 1.602 × 10-19 J. The rest mass of an electron is 9.11 × 10-31 kg
An alpha particle with a kinetic energy of 12.0 MeV makes a head-on collision with a gold nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point charge. A gold nucleus has 79 protons, and an alpha particle is a helium nucleus consisting of two protons and two neutrons. The mass of an alpha particle is 6.64424 x 10-27 kg....
the annihilation of an electron and a positron, each with negligible kinetic energy, results in the production of two photons with the same energy. (a) Determine the energy of each photon in MeV. MeV (b) Determine the wavelength of each photon. m
An alpha particle with a kinetic energy of 10.0 MeV makes a head-on collision with a gold nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point change. The atomic number of gold is 79, and the alpha particle is a helium nucleus consisting of 2 protons and 2 neutrons).