the annihilation of an electron and a positron, each with negligible kinetic energy, results in the production of two photons with the same energy. (a) Determine the energy of each photon in MeV. MeV (b) Determine the wavelength of each photon. m
the annihilation of an electron and a positron, each with negligible kinetic energy, results in the production of two photons with the same energy. (a) Determine the energy of each photon in MeV. MeV...
the annihilation of an electron and a positron, each with negligible kinetic energy, results in the production of two photons with the same energy. (a) Determine the energy of each photon in MeV. MeV (b) Determine the wavelength of each photon. m
2. Electron-positron annihilation A positron with kinetic energy equal to twice its rest mass energy is incident on an electron at rest The positron and electron annihilate creating two photons. One photon goes off at an angle of 30 with respect to the incident positron. Compute the energies of the two photons and find the direction in which the second photon travels 2. Electron-positron annihilation A positron with kinetic energy equal to twice its rest mass energy is incident on...
8-14 positron-electron annihilation A positron et of mass m and kinetic energy K is annihilated on a target containing electrons e(same mass m) practically at rest in the laboratory frame: et(fast) +e-(at rest) → radiation a By considering the collision in the center-of- momentum frame (the frame of reference in which the total momentum of the initial particles is equal to zero), show that it is necessary for at least two gamma rays (rather than one) co result from the...
An electron-positron pair is produced by a 2.85 MeV photon. What is the kinetic energy of the positron if the kinetic energy of the electron is 1.219 MeV? Use the following Joules-to-electron-Volts conversion 1eV = 1.602 × 10-19 J. The rest mass of an electron is 9.11 × 10-31 kg Please answer in MeV
An electron-positron pair is produced by a 2.30 MeV photon. What is the kinetic energy of the positron if the kinetic energy of the electron is 0.958 MeV? Use the following Joules-to-electron-Volts conversion 1eV = 1.602 × 10-19 J. The rest mass of an electron is 9.11 × 10-31 kg
3. A photon creates a electron-positron pair. The kinetic energy of the electron is 2.20 times that one of the positron. What is the kinetic energy of the electron if the energy of the photon is 2.80 times the rest mass energy of the electron? (The rest mass of a electron is 9.11 x10-31 kg.) O 0.128 MeV O 0.819 MeV O 0.281 MeV O 0.409 MeV O 0.186 MeV
An electron (rest mass me) of energy E makes a head-on collision with a positron (positron is electron’s antiparticle, it has the same mass as electron, but opposite charge) In collision the two particles annihilate each other and are replaces by two photons (γ rays) of equal energy, each traveling at equal angles θ with electron’s direction of motion. Find 1. The energy of each photon. 2. The momentum p of each photon. 3. The angle θ. Problem 3. Electron-positron...
How much total kinetic energy will an electron-positron pair have if produced by a 3.64 MeV photon? In MeV
11 The energy of an annihilation photon (511 keV) corresponds to the: A: Speed of light in vacuum B: Rest-mass energy equivalent of 1 electron C: Binding energy of a PET-isotope D: Total sum of the electron and positron rest mass 12 An annihilation photon has the frequency: A: 511 MHz B: 1.235E+20 Hz C: 1.235E+17 Hz D: 7.712E+38 Hz 13 An annihilation photon has the wave-length: A: 1.522E-12 m B: 1.235E-12 m C: 2.427E-12 m D: 0.102E-10 m 14...
Find the wavelength of the two photons resulting from a collision of an electron‐positron pair with kinetic energy of 420keV each