Question

11 The energy of an annihilation photon (511 keV) corresponds to the:
A: Speed of light in vacuum	B: Rest-mass energy equivalent of 1 electron
C: Binding energy of a PET-isotope	D: Total sum of the electron and positron rest mass
12 An annihilation photon has the frequency:
A: 511 MHz	B: 1.235E+20 Hz
C: 1.235E+17 Hz	D: 7.712E+38 Hz
13 An annihilation photon has the wave-length:
A: 1.522E-12 m	B: 1.235E-12 m
C: 2.427E-12 m	D: 0.102E-10 m
14 An electron-positron annihilation event CANNOT generate:
A: 2 photons	B: 3 photons
C: 4 photons	D: 1 photon
15 A particle with kinetic energy equal to its rest energy moves with the velocity:
A: 2.998 E8 m/s	B: 1.517 E8 m/s
C: 2.596 E6 m/s	D: 2.596 E8 m/s
16 An electron moves in the magnetic field of 1 T with velocity of 1E6 m/s perpendicularly to the field lines (i.e. its velocity vector is perpendicular to the B-vector of the magnetic field). What force is acting on this electron?
A: 0 N	B: 1E6 N
C: 1.602E-13 N	D: 1 N
17 An electron moves in the magnetic field of 1 T with velocity of 1E6 m/s in parallel to the field lines (i.e. its velocity vector is parallel to the B-vector of the magnetic field). What force is acting on this electron?
A: 0 N	B: 1E6 N
C: 1.602E-13 N	D: 1 N
18 A neutron moves in the magnetic field of 1 T with velocity of 1E6 m/s perpendicularly to the field lines (i.e. its velocity vector is perpendicular to the B-vector of the magnetic field). What force is acting on this neutron?
A: 0 N	B: 1E6 N
C: 1.602E-13 N	D: 1 N

Answer 1

11. B The Rest mass energy equivalent of 1electron.

12. B. ,

13. C

14. D 1photon

15.D

16. C ( )

17. A 0 N because sin is zero

18 A 0 no charge on neutron

#Hi, I am providing you the solution for all the questions you have asked. If you are happy and find this useful please thumbs up. In case, I f you have any further query regarding the solution please let me know in the comments section below. Thanks!!