what maximum amount of ammonia in kilograms can be synthesized from
5.22 kg of H2 and 31.5 kg of N2?
Balanced chemical reaction-
N2 + 3H2 - 2NH3
first we find the limiting reagent than we calculate the maximun yield.
Molar mass of N2- 28 g = 28/1000 = .028kg
Molar mass of H2- 3×2 = 6 g = 6/1000 = .006 kg
0.28 kg of N2 for completereaction require.006 kg of H2
1 kg of N2 for completereaction require .006/.028 kg of H2
31.5 kg N2 for complete reaction require 0.006*31.5/.028 =6.75 kg
0.006 kg of H2 for completereact require 0.028 kg of N2
1 kg kg of H2 for complete reaction require 0.028/0.006 kg of N2
5.22 kg of H2 .for complete reaction require 0.028*5.22/0.006 = 24.36 kg
We have H2 on 5.22 kg. Means H2 is limiting reagent.
0.006 kg of H2 on complete reaction gives 0.034 kg of amonia
1 kg of H2 on complete reaction gives 0.034/.006 kg of ammonia
5.22kg of H2 .on complete reaction gives 0.034*5.22/.006 = 29.58 kg
what maximum amount of ammonia in kilograms can be synthesized from 5.22 kg of H2 and...
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