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Ammonia can also be synthesized by the reaction: 3H2(g)+N2(g)→2NH3(g) What is the theoretical yield of ammonia,...

Ammonia can also be synthesized by the reaction:

3H2(g)+N2(g)→2NH3(g)

What is the theoretical yield of ammonia, in kilograms, that we can synthesize from 5.22 kg of H2 and 33.5 kg of N2?

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Answer #1

The molecular weight of:

According to the reaction two moles of ammonia is formed from three moles of hydrogen and one mole of nitrogen.

Now 5.22 kg of hydrogen is equivalent to(5.221000)/2 =2610 moles of hydrogen. And 33.5 kg of nitrogen is equivalent to (33.51000)/28=1196.4 moles of nitrogen.Here 1196.4 moles of nitrogen will react with (31196.4)=3589.2 moles of hydrogen,but available hydrogen is only 2610 moles here. So nitrogen is not completely consumed and hence hydrogen is the limiting reagent.So the amount of ammonia which is formed from 2610 moles of hydrogen is  ​​​​​​​

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