Derive the equation e/m = (3.29x106)*(Va)/(I2)(R2) for the charge to mass ratio of an electron using the following equations (Make sure to include how you divided out the units for each component to end up with a final answer that is in C/kg):
(1): (e)(Va) = 1/2 mv2
(2): R = mv/eB
(3): B = ((4/5)3/2 ) * (µ0)(N)(I)/r where µ0 = 4π × 10−7 H/m ; N = 130; and r = 0.15m
Derive the equation e/m = (3.29x106)*(Va)/(I2)(R2) for the charge to mass ratio of an electron using...
Derive the equation e/m = (3.29x106)*(Va)/(I2)(R2) for the charge to mass ratio of an electron using the following equations: (1): (e)(Va) = 1/2 mv2 (2): R = mv/eB (3): B = ((4/5)3/2 ) * (µ0)(N)(I)/r where µ0 = 4π × 10−7 H/m ; N = 130; and r = 0.15m
Finding the charge to mass (e/m) ratio of the electron Often in physics, we look for ways to find fundamental physical constants. From the set-up demonstrated in class, we are able to find a monumental combination of two physical constants-the charge of an electron (e) and the mass of an electron (m). Since the charge of an electron (e) is well known through other experiments, we will use the ratio of charge to mass to find the mass of an...
Finding the charge to mass (e/m) ratio of the electron Often in physics, we look for ways to find fundamental physical constants. From the set-up demonstrated in class, we are able to find a monumental combination of two physical constants-the charge of an electron (e) and the mass of an electron (m). Since the charge of an electron (e) is well known through other experiments, we will use the ratio of charge to mass to find the mass of an...
6. Using the equation of the magnetic field due to a single ring of charge, derive the formula for the magnetic field at the midpoint between the two coils (see Fig. 2). Your expression should be in terms of N (the number of turns in one coil), I, and R. MOIR² Biot -savart Law Bloop = 2(R2 + z2)3/2 No cau xo - No. Il xr uit 12 un 12 periment 7: Charge to Mass Ratio IVlagiel llen Magnetic Forces...
PHY 132: Charge to Mass Ratio of the Electron PHY 132: Charge to Mass Ratio of the Electron Constant Voltage If we rearrange Equation 1, we get the following: B - (m/e) x 2v}"2 x (1/r) Set the voltage to 200 V. Set the current so that the path diameter is 5.0 cm. Increase the path diameter in steps of 0.5 cm (by adjusting the current) until it is equal to 8.0 cm. Fill in the values of the current...
By what factor does the radius of the electron beam path (r) change if the current through the Helmholtz coil (I) is doubled? Hint: Use e/m = 2V (5/4)3 a2/(N 4o Ir)2. the radius of the electron beam path increases by a factor of 2 the radius of the electron beam path increases by a factor of 4 the radius of the electron beam path decreases by a factor of the radius of the electron beam path decreases by a...
Basic Coulomb's law tells us that the electric field of a point charge q, E=ke q/r2, scales with distance r as 1/r2: when the distance increases by a factor of 2, the magnitude of the field decreases by a factor of 4. We can write this as E(r) ∝ 1/r2. An interesting and practically important question is how the electric field of a group of charges scales with distance (asymptotically) far away from the group. The figure below depicts 3...
An electron (charge (e) = 1.6 x 10-19 C, mass (me = 9.1 x 10-31 kg) that trapped inside a magnetic field observed m oving at 3 x 104 m/s speed along a circular path perpendicular to the magnetic field. The magnitude of the magnet ic field is 1.4 T. Х Х X X X Х X x x X Х X v=3 X 10 m/s X X X X 1 Х X X X X X X X x...
3 (b) The energy of a Bohr atom in the n-th excited state is given by the formula E--a2mc2 2,7, where α-e2/(4πέρ,10hc)-1 /137, m is the electron mass and e denotes the electron electric charge. i) Why is the total energy negative? Explain briefly your answer. ii) What is the radius of the electron in the n-th excited state in the Bohr atom? To answer that correctly follow the next steps Use Bohr's angular momentum quantization principle to obtain an...
Help 2) The electric field E 5000 N/C , charge q-2 C ' mass m :5 grams. Calc. qE, then apply the acceleration of this charge. Hint: calc. force F newton's 2nd law. A) 1 m/s2 B) 2 m/s2 C) 3 m/s2 D) 4 m/s2 3) The electric field is E 10,000 N/Ci, displacement d - 5 cm at 60 (angle relative to positive x axis), charge q charge in microJoules (106 J) A) 1.25 B) 2.5 C) 3.75 D)...