9.18 In corn, a colored aleurone is due to the presence of an R allele; r/r...
9.18 In corn, a colored aleurone is due to the presence of an R allele; r/r is colorless. Another gene controls the color of the plant, with g/g being yellow and G_ being green. A plant of unknown genotype is test-crossed, and the following progeny plants were obtained.
Colored green 89
Colored yellow 13
Colorless green 9
Colorless yellow 92
-
What was the phenotype and genotype of the plant used for the test cross?
-
What were the phenotypes of the plants used to produce the plant with the unknown genotype? (Assume that the parentals were homozygous.)
-
What is the approximate map distance between the R locus and the G locus?
Homework Answers
here the progenies of testcross include all four phenotypes that is
Colored green
Colored yellow
Colorless green
Colorless yellow
so the genotype of the plant crossed to the tester (a tester is homozygous recessive ) has all four alleles, which means the plant is dihybrid.
RrGg * rrgg
| RG | Rg | rG | rg | |
| rg | RrGg (colored green) | Rrgg ( colored, yellow) | rrGg (colorless, green) | rrgg (colorless, yellow) |
if the genes are not linked all four phenotypes are expected in the equal proportion that is 25% each but here all four phenotypes are not observed in equal proportion.
Colored green 89
Colored yellow 13
Colorless green 9
Colorless yellow 92
the recombination frequency in percentage is the distance between genes in the map units, maximum recombination ( when the genes are not linked ) is 50%, so if the genes are linked the recombination frequency is less than 50%.
recombination frequency= ( number of recombinant progenies/total
number of progenies)
100
so recombination frequency is the percentage of recombinant progenies if the genes are linked the number of recombinant progenies is less than the number of parental type progenies, so here
Colored yellow 13
Colorless green 9
are recombinant progenies, Rrgg ( colored, yellow) and rrGg (colorless, green) are recombinant progenies developed from the recombinant gametes Rg and rG respectively so the parental type gametes are RG and rg.
so RG alleles came from one parent and rg came from another parent so the genotype of the true-breeding parents which gave rise to dihybrid is RRGG and rrgg.
recombination frequency= ( (number of colored yellow+ number of
colorless green )/ total number)100
= ( ( 13+9)/203)100
= 10.84 %
genotype of the plant is RG/rg
genotype of the parents are RRGG and rrgg
distance between the genes is 10.84 cM.
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9.18 In corn, a colored aleurone is due to the presence
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The table below shows the F1 progeny that result from
selfing four different parent pea plants.
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Part A - Deducing phenotypes and genotypes of selfed parents
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the round allele (R) is dominant to the wrinkled allele
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the yellow allele...
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Concerning the four corn genes below
a) For the following corn genotypes, indicate the expected
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1) Cc Rr pp yy
2) CC rr PP yy
3) Cc Rr Pp YY
4) CIc Rr Pp yy
5) CIC Rr pp Yy
b) From the following corn crosses, list all of the expected
genotypes, corresponding phenotypes, and the ratios (phenotypic and
genotypic) that you would expect among the progeny. List only the
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it should be something like this. please i need a detailed
explaintion on the answers to understand whats going
on.thanks
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Mendel studied pea plants dihybrid for seed shape (round versus
wrinkled) and seed color (yellow versus green). Recall that
the round allele (R) is dominant to the wrinkled allele
(r) and
the yellow allele (Y) is dominant to the green allele
(y).
The table below shows the F1 progeny that result from
selfing four different parent pea plants.
Use the phenotypes of the F1 progeny to deduce the
genotype and...
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where alleles at separate loci assort independently into gametes at
meiosis. You will also use logic to determine unknown genotypes,
phenotypes, and genetic ratios from given data.
Part A - Deducing phenotypes and genotypes of selfed parents
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the round allele (R) is dominant to the wrinkled allele
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the yellow allele...
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