Question

I am having trouble figuring out why my program will not make any columns, just rows. I need to display a square. The instructions are provided below. (This for my C++ class)

Write a program that displays a square. Ask the user for the square’s size. Only accept positive integer numbers (meaning choose a data type that holds positive integer values). The size the user gives you will determine the length and width of the square. The program should then display a square on the screen made of asterisks (*). Hint: Since the program must use for loops, you will need to use nested for loops to execute this properly.

This is my first coding:

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{

int row = 0; // Number of rows displayed
int column = 0; // Number of columns displayed
unsigned int square; // Number from user to use as length and width
int total; // Accumulator for row
int total2; // Accumulator for column

cout << "What number do you want the length and width of your square to be?" << endl;
cin >> square;

total= 0; // Initialized accumulator
for (row = 0; row < square; row++)
{
cout << "*" << endl;
total += row;

total2 = 0; // Initialize accumulator
for (int column = 0; column < square; column++)
{
cout << '*' << endl;
total2 += column;
}
}

return 0;

}

This is my second coding:

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{

int row = 0; // Number of rows displayed
int column = 0; // Number of columns displayed
unsigned int square; // Number from user to use as length and width

cout << "What number do you want the length and width of your square to be?" << endl;
cin >> square;

for (row = 0; row < square; row++)
{
cout << "*" << endl;

for (int column = 0; column < square; column++)
{
cout << '*' << endl;
}
}

return 0;

}

Answer 1

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

int row = 0; // Number of rows displayed

int column = 0; // Number of columns displayed

unsigned int square; // Number from user to use as length and width

cout << "What number do you want the length and width of your square to be?" << endl;

cin >> square;

for(int j=1; j<=square; j++)

{

for(int i=1; i<=square; i++)

{

if(j ==1 || j==square || i==1 || i==square)

{

cout<<"*";

}

else

{

cout<<" ";

}

}

cout<<endl;

}

return 0;

}

=========================================
SEE OUTPUT

This is the square you want to display ?

PLEASE COMMENT if there is any concern.

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