A 2 kg ice puck, moving east with a speed of 3m/s has a head-on collision with a 1.2 kg puck initially at rest. What is the speed of the 2 kg puck after the collision??
Mass of the first puck=m1=2kg
Mass of the second puck=m2=1.2kg
Velocity of the first puck before collision= v1=3m/s
Velocity of the second puck before collision = v2=0m/s
Velocity of the first puck after collision= v1’
For head-on collision use equation,
v1’=[(m1-m2)/(m1+m2)]*v1
Plug values,
v1’=[(2kg-1.2kg)/(2kg+1.2kg)]*(3m/s)
v1’=0.75m/s
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