Question

The position of a particle is described by the function x = 3.0 t2 + 5.0 t + 3.0 (m). Determine the average velocity (in m / s) for the time interval t1 = 2.0 s and t2 = 4.0 s.

Answer 1

here,

x = 3 t^2 + 5 t + 3

at t1 = 2 s

x1 = 3 * (2)^2 + 5 * (2) + 3 m

x1 = 25 m

at t2 = 4 s

x2 = 3 * (4)^2 + 5 * (4) + 3 m

x2 = 71 m

the average velocity , v = ( x2 - x1)/(t2 - t1)

v = ( 71 - 25) m /(4 - 2) s

v = 23 m/s