A particle at t1 = -2.0 s is at x1 = 5.0 cm and at t2 = 5.0 s is at x2 = 8.9 cm . What is its average velocity over this time interval? Can you calculate its average speed from these data?
A rolling ball moves from x1 = 8.8 cm to x2 = -4.6 cm during the time from t1 = 2.9 s to t2 = 6.0 s. What is its average velocity over this time interval?
The position of a particle is described by the function x = 3.0 t2 + 5.0 t + 3.0 (m). Determine the average velocity (in m / s) for the time interval t1 = 2.0 s and t2 = 4.0 s.
A bal moves from a position of x1=3.4 cm to a position of x2=-4.2 cm durint a time t1=3.0 to t2= 6.1 s 1. total distance 2.displacement 3. averange velocity 4. average speed in the time interval
A rolling ball moves from x1 = 8.5cm to x2 = -4.2cm during the time from t1 = 3.0s to t2 = 6.7s What is its average velocity over this time interval?
Table 3.1 Time, t (s) Position, x (m) tn/t1 Time Squared, t^2 (s^2) (tn)^2/(t1)^2 xn/x1 t1, 0.40 x1, 0.25 1.0 .16 1 1 t2, 0.80 x2, 0.36 2.0 .64 4 1.4 t3, 1.2 x3, 0.52 3.0 1.4 9 2.1 t4, 1.6 x4, 0.71 4.0 2.6 16 2.8 t5, 2.0 x5, 0.95 5.0 4.0 25 3.8 t6, 2.4 x6, 1.2 6.0 5.8 36 4.8 Linear fit equation for Position Vs. Time: 0.545x - 0.0530 Quadratic fit equation for Position Vs. Time:...
An object undergoes uniformly accelerated motion from point x1 = 6 m at time t1 = 3 s to point x2 = 46 m at time t2 = 8 s. (The direction of motion of the object does not change.) (a) If the magnitude of the instantaneous velocity at t1 is v1 = 2 m/s, what is the instantaneous velocity v2 at time t2?
8. A student rolls a marble alongside a meterstick to measure its velocity. At t1 = -2.5 s, its position is x1 = 4.3 cm, and at t2 = 4.5 s it is at x2 = 18.5 cm. Determine its average velocity during this time interval. 9. The position of a ball rolling along a straight line is given by ? = 1.8−3.6? +1.5?2, where x is in meters and t is in seconds. Determine the average velocity of the...
A car moves along a straight street. The car’s initial position at time t1 is given by a position vector x! . The car’s later position vector is x2! at time t2. Suppose x1! = 700 miˆ . and x2! =400miˆ. a. If t2 – t1 = 3.0 seconds, what is the car’s average speed (assuming the car only moved in one direction)? b. What was the car’s average velocity?
rolling ball moves from x1 = 8.2 cm to x2 = -4.5 cm during the time from t1 = 2.8 s to t2 = 6.7 s
1) An object undergoes uniformly accelerated motion from point x1 = 6 m at time t1 = 3 s to point x2 = 47 m at time t2 = 7 s. (The direction of motion of the object does not change.) (a) If the magnitude of the instantaneous velocity at t1 is v1 = 2 m/s, what is the instantaneous velocity v2 at time t2? (b) Determine the magnitude of the instantaneous acceleration of the object at time t2. 2)...