A rolling ball moves from x1 = 8.8 cm to x2 = -4.6 cm during the time from t1 = 2.9 s to t2 = 6.0 s. What is its average velocity over this time interval?
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A rolling ball moves from x1 = 8.8 cm to x2 = -4.6 cm during the time from t1 = 2.9 s to t2 = 6.0 s. What is its average velocity over this time interval?
A rolling ball moves from x1 = 8.5cm to x2 = -4.2cm during the time from t1 = 3.0s to t2 = 6.7s What is its average velocity over this time interval?
rolling ball moves from x1 = 8.2 cm to x2 = -4.5 cm during the time from t1 = 2.8 s to t2 = 6.7 s
A particle at t1 = -2.0 s is at x1 = 5.0 cm and at t2 = 5.0 s is at x2 = 8.9 cm . What is its average velocity over this time interval? Can you calculate its average speed from these data?
A bal moves from a position of x1=3.4 cm to a position of x2=-4.2 cm durint a time t1=3.0 to t2= 6.1 s 1. total distance 2.displacement 3. averange velocity 4. average speed in the time interval
EXAMPLE 3 Show that the average velocity of a car over a time interval [t1, tz] is the same as the average of its velocities during the trip. SOLUTION If s(t) is the displacement of the car at time t, then, by definition, the average velocity of the car over the interval is s(t2) - s(tı) As At On the other hand, the average velocity function on the interval is Vave = v(t) dt = s'(t) dt t2 t-taf. “t,'t...
8. A student rolls a marble alongside a meterstick to measure its velocity. At t1 = -2.5 s, its position is x1 = 4.3 cm, and at t2 = 4.5 s it is at x2 = 18.5 cm. Determine its average velocity during this time interval. 9. The position of a ball rolling along a straight line is given by ? = 1.8−3.6? +1.5?2, where x is in meters and t is in seconds. Determine the average velocity of the...
Constants | Periodic Table Part A A rolling ball moves from 1-3.2 cm to z2-4.5 cm during the time from t 3.1s tot2 -5.4s What is its average velocity? Express your answer using two significant figures. 0- cm/s Submit tAnswer Provide Feedback
A rhinoceros is at the origin of coordinates at time t1=0. For the time interval from t1 to t2 = 13.0 s , the rhino's average velocity has x-component -3.2 m/s and y-component 6.0 m/s . At time t2= 13.0 s what is the x-coordinate of the rhino? At time t2= 13.0 s what is the y-coordinate of the rhino? How far is the rhino from the origin?
An object undergoes uniformly accelerated motion from point x1 = 6 m at time t1 = 3 s to point x2 = 46 m at time t2 = 8 s. (The direction of motion of the object does not change.) (a) If the magnitude of the instantaneous velocity at t1 is v1 = 2 m/s, what is the instantaneous velocity v2 at time t2?
Table 3.1 Time, t (s) Position, x (m) tn/t1 Time Squared, t^2 (s^2) (tn)^2/(t1)^2 xn/x1 t1, 0.40 x1, 0.25 1.0 .16 1 1 t2, 0.80 x2, 0.36 2.0 .64 4 1.4 t3, 1.2 x3, 0.52 3.0 1.4 9 2.1 t4, 1.6 x4, 0.71 4.0 2.6 16 2.8 t5, 2.0 x5, 0.95 5.0 4.0 25 3.8 t6, 2.4 x6, 1.2 6.0 5.8 36 4.8 Linear fit equation for Position Vs. Time: 0.545x - 0.0530 Quadratic fit equation for Position Vs. Time:...