How much energy is lost by a 30.0g sample of iron that decreases in temperature from 56.7C to 25.0C? What if instead of iron it was a sample of water ?
SHOW WORK!!!!!
1) For iron
Given:
m = 30 g
C = 0.45 J/g.oC
Ti = 56.7 oC
Tf = 25 oC
use:
Q = m*C*(Tf-Ti)
Q = 30.0*0.45*(25.0-56.7)
Q = -428 J
Answer: 428 J
2) for water:
Given:
m = 30 g
C = 4.184 J/g.oC
Ti = 56.7 oC
Tf = 25 oC
use:
Q = m*C*(Tf-Ti)
Q = 30.0*4.184*(25.0-56.7)
Q = -3979 J
Answer: -3.98*10^3 J
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