Indium has 2 isotopes. The 113-In isotope has a mass of 112.90406184 amu and a percent abundance of 4.290%. What is the mass (amu) of the other isotope?
Given that,
Mass of first isotope 113 In is 112.90406184 amu
Its percentage abundance = 4.290 % = 0.04290
Mass of second 115 In isotope = x (say)
Its abundance = 100 - 0.04290 = 0.9571
Atomic mass of indium = 114.818 amu
But atomic mass = (Mass of first isotope *its abundance)+ (Mass of 2nd isotope *its abundance)
114.818 amu = (112.90406184 *0.04290 ) + ( x * 0.9571)
x = 114.9 amu
Thus, the mass of 2nd isotope = 114.9 amu
Indium has 2 isotopes. The 113-In isotope has a mass of 112.90406184 amu and a percent...
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