Let 'x' is the % abundance for 115.3026 amu.
Then (100-x) will be abundance of 122.8251 amu.
Now,
115.3026*x + 122.8251*(100-x) / 100 = 118.1471
115.3026x + 12282.51 - 122.8251x = 11814.71
7.5225x = 467.8
x = 62.19 % .... Answer
If the mass of the only two isotopes of an element are 115.3026 amu and 122.8251...
5. An element consists of two isotopes in the indicated natural abundances: Isotope A, mass=84.9118 amu, abundance = 72.15% Isotope B, mass = 86.9092 amu, abundance = 27.85% What is the atomic weight of this element? What is the identity of the element? Show your calculations.
< Question 4 of 17 > Suppose that a fictitious element, X, has two isotopes: 59X (59.015 amu) and "x (62.011 amu). The lighter isotope has an abundance of 75.7%. Calculate the average atomic mass of the element X average atomic mass:
the element X has naturally occurring isotope. The masses (amu) and % abundance of the isotopes are given below. the average atomic mass of the element is ? Isotope: 221X, 220X, 218 X Abundance: 74.22, 12.78, 13.00 Mass: 220.9, 220.0, 218.1
8. An element has two naturally occurring isotopes. Isotope 1 has a mass of 120.9038 amu and a relative abundance of 57.4%. Isotope 2 has a mass of 122.9042 amu. Find the atomic mass of this element and, by comparison to the periodic table, identify it.
The element lanthanum has an atomic weight of 139 and consists of two stable isotopes lanthanum-138 and lanthanum- 139. The isotope lanthanum-138 has a mass of 138 amu and a percent natural abundance of 8.90X10-2 %. The isotope lanthanum-139 has a percent natural abundance of 99.9%. What is the mass of lanthanum-1392 A certain element consists of two stable isotopes. The first has a mass of 113 amu and a percent natural abundance of 4.28 %. The second has a...
1. An element has two naturally occurring isotopes. Isotope 1 has a mass of 120.9038 amu, and a relative abundance of 57.4%. Isotope 2 has a mass of 122.9042, and a relative abundance of 42.6%. Find the atomic mass of this element and identify it by name and symbol.
The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table below. The average atomic mass of the element is _ _amu. Isotope Abundance (%) Mass (amu) 221X 74.22 220.90 12.78 220.00 2187 13.00 218.10 2207 219.70 220.34 220.43 219.00 33.333
Element X has two natural isotopes: X-6 (6.015 amu) and X-7 (7.016 amu). Calculate the atomic mass of element X given the abundance of X-7 is 92.5%. a. 6.09 amu b. 6.50 amu 6.52 amu d 6.94 amu e. 12.5 amu
The element europium (Z = 63) has two naturally occurring isotopes. One of the isotopes is 151 Eu, which has a mass of 150.9198 amu and a natural abundance of 47.81%. Calculate the mass of the other isotope. (Answer. 152.9 amu)
The element carbon has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table below. Isotope 12c isotopic mass (amu) Abundance (%) 12.00 13.00 98.93 1.07 Calculate the average atomic mass of carbon to two digits after the decimal point. Number = _______ amu