A survey asked, “On the average day, about how many hours do you personally watch TV?”...
A survey asked, “On the average day, about how many hours do you personally watch TV?” Below is the data summary:
| Variable | N | Mean | SE 95% CI |
| TV Hours | 892 | 2.76 | 0.08 (2.60, 2.93) |
(1.1) A student who has not taken SOC 210 offers this interpretation of the confidence interval: “There is a 95% chance that average TV hours is between 2.60 and 2.93 hours per day.” What is wrong with this interpretation? State the correct interpretation.
Homework Answers
He is wrong because he makes a claim about the average TV hours
being between 2.6 and 2.93 with a probability of 95%. A 95%
Confidence Interval means that 95 out of 100 times our method of
estimating the interval will be successful. In other words, in the
long run 
of the time this method will be unsuccessful. Note that a
confidence interval is a statement about the method of estimating
the interval and not about the true parameter.
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A survey asked, “On the average day, about how many hours do you
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3. How much TV do College Students watch? In a survey 361 students were asked how...
3. How much TV do College Students watch? In a survey 361 students were asked how many hours of TV they watched per week. The sample gave an average of 6.504 hours. A bootstrap distribution gave a SE of 0.2939. Find and interpret a 90% confidence interval for the average number of hours a student watches TV per week.
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A survey asked people, "How many hours do you spend watching reality TV shows per week?". From a random sample of 1200 people, sample mean was 9.5 and the (sample) standard deviation was 3.1 hours. Construct a 90% confidence interval for population mean A (6.4, 12.6) B. Cannot compute based on the given information. C-19.32, 9.68) D.(4.4, 15.6) E. (9.35, 9.65) QUESTION 20 (Continue from the previous question) what is the minimum required sample size to make sure that the...
3. How much TV do College Students watch? In a survey 361 students were asked how many hours of TV they watched per week. The sample gave an average of 6.504 hours. A bootstrap distribution gave a SE of 0.2939. Find and interpret a 90% confidence interval for the average number of hours a student watches TV per week.
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