Question

3. How much TV do College Students watch? In a survey 361 students were asked how many hours of TV they watched per week. The sample gave an average of 6.504 hours. A bootstrap distribution gave a SE of 0.2939. Find and interpret a 90% confidence interval for the average number of hours a student watches TV per week.

Answer 1

(a)

$\alpha$ = 0.10

From Table, critical values of Z = $\pm$ 1.645

Confidence Interval:

6.504 $\pm$ (1.645 X 0.2939)

= 6.504 $\pm$ 0.4835

= (6.0205 ,6.9875)

Confidence Interval:

6.0205 < $\mu$ < 6.9875

(b)

Interpretation:

The 90% Confidence Interval (6.0205 ,6.9875) is a range of values that is likely to contain an unknown population mean number of hours a student watches TV per week. If we conduct the experiment many times and calculate confidence interval in each experiment, 90% of the confidence intervals will contain an unknown population mean number of hours a student watches TV per week.