Question

Hi

May I ask how can I do this:

provided a list [1,2,3,4] and

return a list as each number added the number before it,

for example, the final list should return as [(1+0),(1+2),(1+2+3),(1+2+3+4)] = [1,3,6,10]

please do in python 3.7, thank you!!!

Answer 1

Given below is the code in python:

listUsed = [1,2,3,4] # Our initial list
listCopy = [1,2,3,4] # a list copy because the changes made in the orginal will reflect in the next iteration

listLen = len(listUsed) # find length of the list
sumList = 0

for i in range(listLen): # Run loop from 0 to listLen-1
for j in range(i+1): # Run loop from 0 to i+1
sumList = listUsed[j] + sumList # find sum of all the previous numbers and current number
  
listCopy[i] = sumList # Assign this sum to the list copy made
sumList = 0 # reinitialise sum as 0 for the next iteration

print(listCopy) # print listCopy