In Drosophila, red eyes is a wild-type phenotype. Several different genes affect eye color. One allele...
In Drosophila, red eyes is a wild-type phenotype. Several different genes affect eye color. One allele causes purple eyes, and a different allele causes sepia eyes. Both of these are recessive to red eye color. When flies with purple eyes were crossed to flies with sepia eyes, all F1 flies had red eyes. When the F1 offspring were allowed to mate, the F2 flies were as follows:
162 purple eyes
172 sepia eyes
58 purplish sepia eyes
478 red eyes
Explain this pattern of inheritance. Use a chi square test to test the goodness of fit of your hypothesis with the data
Homework Answers
Answer:
Dihybrid F2 phenotypic ratio = 9:3:3:1
Dominant/dominant = 9/16
Dominant/recessive = 3/16
Recessive / dominant = 3/16
Recessive / recessive = 1/16
Total progeny = 870
purple eyes = 870 * 3/16 = 163.125
sepia eyes = 870 * 3/16 = 163.125
purplish sepia eyes= 870 * 1/16 = 54.375
red eyes = 870 * 9/16 = 489.375
|
Phenotype |
Observed(O) |
Expected (E) |
O-E |
(O-E)2 |
(O-E)2/E |
|
Red eyes |
478 |
489.38 |
-11.375 |
129.391 |
0.264 |
|
purple eyes |
162 |
163.13 |
-1.125 |
1.266 |
0.008 |
|
sepia eyes |
172 |
163.13 |
8.875 |
78.766 |
0.483 |
|
purplish sepia eyes |
58 |
54.38 |
3.625 |
13.141 |
0.242 |
|
Total |
870 |
870 |
0.997 |
Chi-square value = 0.997
Degrees of freedom = Number of phenotypes – 1
Df = 4-1=3
Critical value 7.81
The chi-square value of 0.997 is less than the critical value of 7.81. We can the accept null hypothesis and the data fit into the hypothesis.
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