Question

BIO340 Recitation 5 Spring 2020 Your professor is having you look at two genes in Drosophila...

BIO340 Recitation 5 Spring 2020

Your professor is having you look at two genes in Drosophila fruit flies to determine experimentally whether they are linked. One trait is eye color and two alleles are present at the gene: se+ is the wild-type allele for red eyes, and se is the mutant, recessive allele for sepia eyes. The second trait is body color and two alleles are present at this gene: e+ is the wild-type allele for grey body, and e is the mutant, recessive allele for ebony body. You have crossed a pure-breeding red-eyed, grey body female by a pure-breeding sepia-eyed, ebony body male to generate F1 heterozygotes for a mapping cross. All the F1 offspring have red eyes and grey bodies. You next cross this F1 with pure-breeding sepia-eyed, ebony body flies and the following results were obtained.

165 red eyes, grey body

136 red eyes, ebony body

166 sepia eyes, ebony body

133 sepia eyes, grey body

A. If the genes were linked, which two phenotypic classes would represent the recombinants?

B. Conduct a Chi-Square analysis to determine if these two genes assort independently.

C. If the genes do not assort independently, calculate the map distance between the two genes.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer:

Expected testcross progeny would be 1:1:1:1 ratio according to Mendel experiments.

Phenotype

Observed(O)

Expected (E)

O-E

(O-E)2

(O-E)2/E

red eyes, grey body

165

150.000

15.00

225.00

1.500

red eyes, ebony body

136

150.000

-14.00

196.00

1.307

sepia eyes, ebony body

166

150.000

16.00

256.00

1.707

sepia eyes, grey body

133

150.000

-17.00

289.00

1.927

Total

600

600

6.440

Chi-square value = 6.44

Degrees of freedom = Number of phenotypes – 1

Df = 4-1=3

Critical value = 7.81

The chi-square value of 6.44 is less than the critical value of 7.81. We can accept the null hypothesis and the two genes are not linked and they assorted independently.

Add a comment
Know the answer?
Add Answer to:
BIO340 Recitation 5 Spring 2020 Your professor is having you look at two genes in Drosophila...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The genes for sepia eye color, short bristles, and dark body coloration are on the same...

    The genes for sepia eye color, short bristles, and dark body coloration are on the same chromosome of Drosophila melanogaster. Each gene has two alleles: wild type, which is dominant, or mutant, which is recessive.             se+ is dominant and causes red eyes; se is recessive and causes sepia eyes             sb+ is dominant and causes long bristles; sb is recessive and causes short bristles             b+ is dominant and causes gray body coloration; b is recessive and causes dark...

  • In Drosophila, red eyes is a wild-type phenotype. Several different genes affect eye color. One allele...

    In Drosophila, red eyes is a wild-type phenotype. Several different genes affect eye color. One allele causes purple eyes, and a different allele causes sepia eyes. Both of these are recessive to red eye color. When flies with purple eyes were crossed to flies with sepia eyes, all F1 flies had red eyes. When the F1 offspring were allowed to mate, the F2 flies were as follows: 162 purple eyes 172 sepia eyes 58 purplish sepia eyes 478 red eyes...

  • genetics: sorted independently and completely linked Analyze the following fruit fly cross. In this cross there...

    genetics: sorted independently and completely linked Analyze the following fruit fly cross. In this cross there are two autosomal traits that are influenced by two distinct genes and the F2 generation came from crossing an F1 male with an F1 female. P: true breeding grey eyed; brown bodied males x true breeding red eyed; black bodied females F1: all offspring are red eyed; brown bodied F2: ? When the Fy flies are allowed to self cross, what percentage of F2...

  • In Genetics lab, you decide to further investigate Drosophila eye color. In addition to studying the...

    In Genetics lab, you decide to further investigate Drosophila eye color. In addition to studying the sepia gene (se), you decide to study the gene mahogany eyes (mo). Flies that are mo-/mo- have brown eyes. You wonder if a fly that is a double mutant for sepia and mahogany eyes would have very dark brown (almost black) eyes. Because se and mo are both on the third chromosome, you have to do a recombination. You look through a former labmate’s...

  • The inheritance of eye color in Drosophila is controlled by genes on each of the fly?s...

    The inheritance of eye color in Drosophila is controlled by genes on each of the fly?s four chromosome pairs. One eye-color gene is on the fly?s X chromosome, so the trait is inherited in a sex-linked manner. For this sex-linked trait, the wild-type (brick red) allele is dominant over the mutant vermilion (bright red) allele. A homozygous wild-type female fly is mated with a vermilion male fly. X+ X+ * X^p Y Predict the eye colors of F1 and F2...

  • The allele se gives Drosophila a sepia body and se+ gives brown, the wild-type phenotype. The...

    The allele se gives Drosophila a sepia body and se+ gives brown, the wild-type phenotype. The allele ro of a separate gene gives rough eyes and ro+ gives smooth eyes, the wild-type phenotype. The allele ss of a third gene gives flies without thorax spines and ss+ gives flies with thorax spines, the wild-type phenotype. When females heterozygous for each of these genes were testcrossed with sepia, rough, spineless males, the following classes and numbers of progeny were obtained: wild...

  • LABORATORY 6. MENDELIAN GENETICS: GENERAL REMARKS AND Drosophila 1. Are the genes for the body color,...

    LABORATORY 6. MENDELIAN GENETICS: GENERAL REMARKS AND Drosophila 1. Are the genes for the body color, eye color, and wing shape recessive or dominant? Explain your answer. Yellow: _______________ White: _________________ Miniature: ____________ Sepia: _________________ Explanation: _________________________________________ _________________________________________ _________________________________________ _________________________________________ _________________________________________ 2. Where are these genes located? On an autosome(s) or sex chromosome? Explain your answer Yellow: _______________ White: _________________ Miniature: ____________ Sepia: _________________ Explanation: _________________________________________ _________________________________________ 2. Set up a X2 to test if the yellow (y) (body color)...

  • 6. In Cross 1, a yellow eyed, long wing fruit fly from a pure breeding strain...

    6. In Cross 1, a yellow eyed, long wing fruit fly from a pure breeding strain is mated to a red eye, short wing fruit fly from a pure breeding strain. All of their offspring (F1) had red eyes and long wings. In Cross 2, one of the F1 offspring is mated to a fly with yellow eyes and short wings, and this cross gave the following F2 population: 194 flies with long wings and red eyes, 796 flies with...

  • the fruit fly, Drosophila melanogaster, an allele (v) of the gene vermillion gives flies purple eyes...

    the fruit fly, Drosophila melanogaster, an allele (v) of the gene vermillion gives flies purple eyes and is recessive to the wildtype red eye color (v+). An allele y of the yellow gene, gives flies a yellow body color compared to the dominant brown body color (yt). A heterozygous females for the two different mutations is test-crossed with mutant (i.e., homozygous recessive) males. The phenotypes of the progeny of this cross and their corresponding numbers are given below Yellow body,...

  • Assortment of genes on same chromosome In the fruit fly Drosophila, there is a dominant gene...

    Assortment of genes on same chromosome In the fruit fly Drosophila, there is a dominant gene for normal wings and its recessive allele for vestigial wings. At another gene locus. there is a dominant gene for red eyes and its recessive allele for purple eyes. A female that was heterozygous at both gene loci was mated with a male that is homozygous for both recessive alleles. Knowing this, complete the sentences with the correct terms. 94% crossing over independent assortment...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT