A method calls for you to prepare 250.0 mL of stock solution of strontium sulfate by...
A method calls for you to prepare 250.0 mL of stock solution of strontium sulfate by weighing 5.000 grams of it into a 500 mL flask and diluting to the mark. The analytical balance has a tolerance of +/- 0.050 grams and the flask has a tolerance of +/- 0.15 mL. Report the concentration of strontium ions in the prepared solution with uncertainty.
Homework Answers
Mass of compound = 5 
0.05 g
Volume of solution = 250 0.15 mL
Concentration of compound = mass / Volume
Concentration of the compound = 0.02 0.0002
g/mL
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A method calls for you to prepare 250.0 mL of stock solution of
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