In an experiment to study the formation of HI(g), H2(g) + I2(g) <=> 2 HI(g) At equilibrium, {H2} = 0.0325, {I2} = 0.0987 and {HI} = 0.085. Calculate the value of Kc. Give your answer to 3 decimal places.
In an experiment to study the formation of HI(g), H2(g) + I2(g) <=> 2 HI(g) At...
Consider the equilibrium reaction. H2(g) + I2(g) equilibrium reaction arrow 2 HI(g) In this case, 1.000 M H2 reacts with 2.000 M of I2 at a temperature of 414°C. The value of Kc = 72. Determine the equilibrium concentrations of H2, I2, and HI. [H2] [I2] [HI]
consider the equilibrium reaction of H2 (g) + I2 (g) <-----> 2 HI (g) it has an equilibrium constant Kc = 54.3 at 430°C. if the initial concentration of [HI]0 = 2.000 M. what are the equilibrium concentrations?
Consider the following reaction: H2 (g) + I2 (g) ⇌ 2 HI (g) Complete the following table. Assume that all concentrations are equilibrium concentrations in M. T(∘C) [H2] [I2] [HI] [Kc] 25 0.0355 0.0388 0.922 − 340 − 4.55×10−2 M 0.384 M 90.6 445 4.90×10−2 M 4.74×10−2 M − 50.2 Find Kc at 25 ∘C. Find [H2] at 340 ∘C. Find [HI] at 445 ∘C.
1/2 H2 (g) + 1/2 I2 (g) <-> HI (g) At a certain temperature, Kc of reaction is 400 If 0.025M of H2 and 0.025 M and 0.065 M of HI are in a 1.00 L container, what is the concentration of HI at equilibrium?
Given the reaction below, H2 (g)+ I2 (g)⇌ 2 HI (g) Kc = 50.5 What was the initial mass of HI (g) placed in a sealed 1.50 L flask which resulted in 0.025 mol of each of H2 (g) and I2 (g) being found in the flask at equilibrium?
Consider this reaction: H 2 (g)+ I 2 (g)⇌2HI(g) H2(g)+I2(g)⇌2HI(g) A rxn mixture in a 3.73 L flask at a certain temperature initially contains 0.766 g H2 and 96.7 g I 2 I2 . At equilibrium, the flask holds 90.3 g HI . Calculate the equilibrium constant (Kc)(Kc) for the reaction at this temperature. Record your answer using two significant figures.
Given the equilibrium reaction: 2HI(g) H2(g) + I2(g) A sample mixture of HI, H2, and 12, at equilibrium, was found to have [H2]- 1.4 x 102 Mand [HI 4.0 x 102 M. If Keq 1.0 x 10, calculate the molar concentration of I2 in the equilibrium mixture, Enter your answer in the provided box. ]= м
Calculate Kc for the following reaction, H2(g) + I2(g) <=> 2 HI(g); Kp = 46.2 at 25.0 o C
Calculate the equilibrium concentrations of H2, I2, and HI at 700 K if the initial concentrations are [H2] = 0.200 M and [I2] = 0.400 M. The equilibrium constant Kc for the reaction following reaction is 57.0 at 700 K. (Show Work) H2(g)+I2(g)<--- ---->2HI(g)
Consider the following reaction: 2 HI(g) H2(g) + I2(g) If 2.29 moles of HI, 0.309 moles of H2, and 0.363 moles of I2 are at equilibrium in a 17.8 L container at 774 K, the value of the equilibrium constant, Kp, is