You just read a report that contained the following boundaries for a 90% confidence interval bassed on a sample proportion of .36: 0.2284 and 0.4916. What was the associated sample size?
Margin of error = (0.4916 - 0.2284)/2 = 0.1316
For 90% confidence, z = 1.645
p = 0.36 So q = 1 - 0.36 = 0.64
Hence,
On solving above for n, we will get:
n = 36
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